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2 years ago

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According to your model, what price should you charge to maximize profit? Explain how you know this is the best price. (Hint: Re

member that x represents change in price from $22, not price.) (3 points: 1 point for price and 2 points for explanation)

1 answer:

nordsb [41]2 years ago

4 0

Answer:

<h2>$30 no decimal include in it so the answer is $30</h2>

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The ratio of boys to girls in a group is 4:1. If there are 33 more boys than girls, work out how many people there are in total.

MissTica

Total number of people is 55

<u>Step-by-step explanation:</u>

Step 1:

Given ratio between boys and girls is 4:1. Let number of girls be x, so number of boys = 33 + x

⇒ 4x + x = x + 33 + x

⇒ 5x = 33 + 2x

⇒ 3x = 33

⇒ x = 11

Step 2:

Find total number of people.

33 + 2x = 33 + 22 = 55

7 0

2 years ago

Read 2 more answers

Rayshad has $238.12 deducted from his monthly annual pay for group insurance. His employer pays 85% of the cost. What is the ann

umka21 [38]

202.402
Explanation
282.12 x .85

5 0

3 years ago

A number decreased by fifteen is less than two.

Aliun [14]

Let us assume number of n.

The number is decreased by 15.

Decreasing by 15 means, we need to subtract 15 from that number.

So, it would be come n-15.

Now, it is said that the number would become less than 2.

So, we need to setup an inequality:

n-15 is less than 2.

<h3>n-15 < 2 : required inequality .</h3>

Adding 15 on both sides, we get

n-15+15 < 2+15

n < 17.

<h3>So, we could say the number would be less than 17.</h3>

3 0

2 years ago

4.) The time X (minutes) for a lab assistant to prepare the equipment for a certain experiment is believed to have a uniform dis

Jet001 [13]

Answer:

$P(35-2 < X 35+2) = P(33< X< 37)= P(X$

And using the cumulative distribution function we got:

$P(35-2 < X 35+2) = P(33< X< 37)= P(X$

The probability that preparation is within 2 minutes of the mean time is 0.134

Step-by-step explanation:

For this case we define the following random variable X= (minutes) for a lab assistant to prepare the equipment for a certain experiment , and the distribution for X is given by:

$X \sim Unif (a= 20, b =50)$

The cumulative distribution function is given by:

$F(x) = \frac{x-a}{b-a} , a \leq X \leq b$

The expected value is given by:

$E(X) = \frac{a+b}{2} = \frac{20+50}{2}=35$

And we want to find the following probability:

$P(35-2 < X 35+2) = P(33< X< 37)$

And we can find this probability on this way:

$P(35-2 < X 35+2) = P(33< X< 37)= P(X$

And using the cumulative distribution function we got:

$P(35-2 < X 35+2) = P(33< X< 37)= P(X$

The probability that preparation is within 2 minutes of the mean time is 0.134

8 0

3 years ago

A rectangle is inscribed in a right isosceles triangle, such that two of its vertices lie on the hypotenuse, and two other on th

Rufina [12.5K]

Answer:

Part 1) The base is $25\ in$ and the height is $10\ in$

Part 2) The base is $7.5\ in$ and the height is $18.75\ in$

Step-by-step explanation:

case 1) Right isosceles triangle of the left

Let

x------> the base of the rectangle

y----> the height of the rectangle

Remember that

In a right isosceles triangle the lengths of the legs of the triangle is the same

$y+x+y=45$

$2y+x=45$ ----> equation A

$\frac{x}{y} =\frac{5}{2}$

$x=2.5y$ -----> equation B

substitute equation B in the equation A

$2y+2.5y=45$

$4.5y=45$

$y=10\ in$

Find the value of x

$x=2.5(10)=25\ in$

case 2) Right isosceles triangle of the right

Let

x------> the base of the rectangle

y----> the height of the rectangle

Remember that

In a right isosceles triangle the lengths of the legs of the triangle is the same

$y+x+y=45$

$2y+x=45$ ----> equation A

$\frac{y}{x} =\frac{5}{2}$

$y=2.5x$ -----> equation B

substitute equation B in the equation A

$2(2.5x)+x=45$

$6x=45$

$x=7.5\ in$

Find the value of y

$y=2.5(7.5)=18.75\ in$

3 0

2 years ago