<span>When a cell is placed in an isotonic solution, the cell will not exprience a change in size. This is because, an isotonic solution is one which contains two different solutions which have the same osmotic pressure across a semi-permeable membrane. This makes it possible for water to move freely across the membrane without changing the concentration of the solutes on either side of the membrane. Thus the cell will not exprience any change in size. Cells placed in an hypertonic solution will shrink because water will be moving out of the cell.</span>
Answer:
Explanation:
Energy is absorbed to break bonds. Bond-breaking is an endothermic process. ... Bond-making is an exothermic process. if a reaction is endothermic or exthermic depends on the difference between the energy needed to break bonds and the energy released when new bonds form.
Answer:
C
Explanation:
Adenosine triphosphate (ATP) links most cellular exergonic and endergonic chemical reactions. To obtain energy to do cellular work, organisms take energy-rich compounds such as glucose into the cell and enzymatically break them down to release their potential energy. Therefore, the organism needs a way to trap some of that released energy and store the energy in a form that can be utilized by the cell to do cellular work. Principally, energy is trapped and stored in the form of adenosine triphosphate or ATP.
Answer:
C. When the chest volume expands, air can now rush in through the puncture without filling the alveoli.
Explanation:
During inhalation, the contraction of the diaphragm and the external intercostals increase the volume of the chest cavity. As the chest cavity expands, the alveolar pressure become lower than the atmospheric pressure resulting in the flow of air into the lungs in response to the pressure gradient.
The chest cavity is an airtight chamber. This ensures that any changes in the volume of are chest cavity corresponds to the volume of the lungs. If a lung is punctured, the air would not fill the punctured lung but would escape through the hole. Therefore, the punctured lung would not be filled with air during inhalation.