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a_sh-v [17]
3 years ago
6

An important challenge to traditional (pre-1860) ideas about species was the observation that seemingly dissimilar organisms suc

h as hummingbirds, humans, and whales have similar skeletal structures. This most directly suggested to biologists that _____.
Biology
1 answer:
katen-ka-za [31]3 years ago
6 0

Answer:

Dissimilar organisms might have evolved from a distant, common ancestor.

Explanation:

First of all we should know species. Species is considered as a basic unit of taxonomic classification of an organism.

Initially, the scientists are agreed on this phenomenon that all distinct species are evolved gradually from common ancestor. Today, the species which are different from each other just like hummingbirds, humans and whales are from the same ancestor but with the time passage genetic mutation occurs and at the end dissimilar organisms we can see in our environment/surroundings.

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If an organism didn't have DNA, it would be missing which sign of life? A. one or more cells B. information system C. response t
Zepler [3.9K]

Answer:

The correct answer would be - option B. information system.

Explanation:

DNA is the unit of heredity as it contains the genetic code of an organism which is carried all the genetic information and transfer from the parent cell to the daughter cell. It also carries the information required for making all essential proteins in an organism.

So, if an organism did not have DNA, it would be missing the information system which is also responsible for the cell division other than given information.

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DNA is found in all the following cell structures EXCEPT the A. nucleus. B. mitochondria. C. chloroplasts D. ribosomes.
Gekata [30.6K]
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ribosomes

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3 0
3 years ago
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Name three ways that native Americans prepared corn that are still used today
Alex Ar [27]

Answer:

With butter

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Explanation:

7 0
3 years ago
In a population of tree frogs, the allele that causes yellow eyes (Y) is dominant over the allele that causes orange eyes (y). I
polet [3.4K]

Hardy-Weinberg Principle

Genotype frequency equation

 p^{2} +2pq +  q^{2} = 1

Where p² is the freq of homo dominant genotype, 2pq is the freq of heterozygous genotype and q² is the freq of homo recessive genotype.

Allele frequency equation

p + q = 1

Where p is the frequency of dominant alleles and q is the frequency of recessive alleles.

Yellow eyes in the frog offspring is a phenotype (physical trait) that would be a expressed by a geneotype (YY or Yy). This frequency, 0.85 includes: p² + 2pq

0.85 + q² = 1

q² = 0.15

p = \sqrt{0.15} 

Then p + \sqrt{0.15}  = 1

1 - \sqrt{0.15} = p

p = 0.613

61%



7 0
3 years ago
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