Triangle CDA is the image of triangle ABC after a 180º rotation around the midpoint of segment AC. Triangle ECB is the image of
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Given:
ΔABC ΔDEF
To find:
The length of median CP
Solution:
In ΔABC,
AP = 12, BP = 12 and PC = 3x - 12
In ΔDEF,
DQ = 16, QE = 16 and FQ = 2x + 8
If two triangles are similar, then their median is proportional to the corresponding sides.
Do cross multiplication.
Add 192 on both sides.
Subtract 24x from both sides.
Divide by 24 on both sides.
⇒ 12 = x
Substitute x = 12 in CP.
CP = 3(12) - 12
= 36 - 12
= 24
The length of median CP is 24.
Answer:
Ques 16)
We have to simplify the expression:
Ques 17)
Ques 18)
Let the blank space be denoted by the quantity 'x'.
Ques 19)
Let the missing quantity be denoted by 'x'.