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Len [333]
2 years ago
14

Find sec \theta given point (7,\sqrt(15)

Mathematics
1 answer:
jonny [76]2 years ago
4 0

The <em>exact</em> value of the <em>secant</em> function of the point (x, y) = (7, √15) is equal to 8 / 7.

<h3>What is the exact value of a trigonometrical function?</h3>

Herein we have the coordinates of a point set on Cartesian plane, which represents the end of the hypotenuse of a <em>right</em> triangle. Now we must find the <em>exact</em> value of the <em>secant</em> function associated to the angle created by that point:

sec θ = 1 / cos θ

By definition of <em>trigonometric</em> functions and Pythagorean theorem:

sec θ = 1 / (x / r)

sec θ = r / x

sec θ = √(x² + y²) / x

If we know that x = 7 and y = √15, then the exact value of the secant function is:

sec θ = √(7² + 15) /7

sec θ = 8 / 7

The <em>exact</em> value of the <em>secant</em> function of the point (x, y) = (7, √15) is equal to 8 / 7.

To learn more on trigonometric functions: brainly.com/question/14434745

#SPJ1

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