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sukhopar [10]
3 years ago
6

A car rental agency has 18 vehicles available, of which 3 are convertibles. What is the probability that a randomly selected veh

icle will be a convertible? Write your answer as a fraction or whole number.
Mathematics
1 answer:
Westkost [7]3 years ago
7 0

Answer:

\frac{1}{6}\\

Step-by-step explanation:

To find the probability, divide the number of desired outcomes by the total:

This will be 3/18, since there are 3 convertibles and there are 18 total cars

Simplify 3/18

= \frac{1}{6}

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Farmer Hanson is putting together fruit baskets. He has 240 apples and 150 pears. What is the largest number of baskets he can p
Tomtit [17]

Answer: 30 baskets.

<u>Step-by-step explanation:</u>

You need to find the Greatest Common Factor (GCF).

240 (apples) = 2 x 2 x 2 x 2 x 3 x 5

150 (pears) = 2 x 3 x 5 x 5

GCF (240, 150) = 2 x 3 x 5

                         = 30

You can make 30 baskets containing 240/30 = 8 apples and 150/30 = 5 pears.

4 0
3 years ago
PLEASE HELP ASAP! IM SO CONFUSED THIS IS DUE SOON!! I NEED HELP! QUESTION IN PICTURE BELOW! HELP NEEDED
gtnhenbr [62]

Answer:

c

Step-by-step explanation:

I took the test, and that was the correct answer. I hope this helps!

5 0
1 year ago
A veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses
Licemer1 [7]

Answer:

Probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

Step-by-step explanation:

We are given that a veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses with colic is 12 years. The average age of all horses seen at the veterinary clinic was determined to be 10 years. The researcher also determined that the standard deviation of all horses coming to the veterinary clinic is 8 years.

So, firstly according to Central limit theorem the z score probability distribution for sample means is given by;

                    Z = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \bar X = average age of the random sample of horses with colic = 12 yrs

            \mu = average age of all horses seen at the veterinary clinic = 10 yrs

   \sigma = standard deviation of all horses coming to the veterinary clinic = 8 yrs

         n = sample of horses = 60

So, probability that a sample mean is 12 or larger for a sample from the horse population is given by = P(\bar X \geq 12)

   P(\bar X \geq 12) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } \geq \frac{12-10}{\frac{8}{\sqrt{60} } } ) = P(Z \geq 1.94) = 1 - P(Z < 1.94)

                                                 = 1 - 0.97381 = 0.0262

Therefore, probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

4 0
3 years ago
What’s 7= y-2/3 if you’re solving for y
Rus_ich [418]

Answer:

y = 23/3

Step-by-step explanation:

Simplify both sides of equation

7 = y + -2/3

Flip equation

y + -2/3 = 7

Add 2/3 to both sides

y + -2/3 + 2/3 = 7 + 2/3

y = 23/3

6 0
3 years ago
What is 29/12 as a decimal
ivolga24 [154]

Answer:

2.4166666666 (6 forever)

Step-by-step explanation:

5 0
3 years ago
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