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Andrew [12]
3 years ago
5

Can anybody help me with these 3 problems they are all division please and thank you

Mathematics
1 answer:
Shkiper50 [21]3 years ago
6 0

Answer:

1. 12

2. 3/28

3. 2

Step-by-step explanation:

1. Multiply both sides by the reciprocal of 1/3 which is 3. So that would be 4 × 3, which equals 12.

2. Multiply both sides by the reciprocal of 7/2, which is 2/7. Then multiply the numerators, (2 × 3) and multiply the denominators, (7 × 8). So the numerator would be 6 and the denominator would be 56. But the fraction isn't simplified; a common number that they can both be divided by is 2. 6 divided by 2 is 3 and 56 divided by 2 is 28, making the final answer be 3/28.

3. 3 1/2 needs to be turned into a complete fraction, so you would mulitply the whole number (3) by the denominator (2) and add the numerator to that answer. That would be 7, and then you multiply both sides by the reciprocal of 7/4 which is 4/7. That makes the fraction 28/14, and you can still divide them by a common number, 14. That makes the final answer 2.

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10.The sum of first 16 terms of the AP: 10, 6 ,2, ....is
madam [21]

Answer:

<h2>               - 320</h2>

Step-by-step explanation:

a₁ = 10

a₂ = 6

d = a₂  - a₁ = 6 - 10 = -4

n = 16

a₁₆ = a₁ + (n-1)•d = 10 + (16-1)•(-4) = 10 - 60 = -50

S_{n}=\dfrac{a_1+a_n}{2}\cdot n\\\\\\S_{16}=\dfrac{10-50}{2}\cdot 16=-40\cdot8=-320

4 0
3 years ago
Y=Cosx.arcsinx<br> What is the solution
Alinara [238K]

Step-by-step explanation:

Given: y = cos(sin^{-1}x))

As the domain for the inverse sine function is 1  ≤  x  ≤  1  as this is the range for the sine function.

The range for the function is the same as the range for the cosine function, 1  ≤  y  ≤  1

As

sin^{2}x +cos^{2}x = 1

So, using the identity cos(x) = \pm \sqrt{1-sin^{2}(x) }

y = \pm \sqrt{1-sin^{2}(sin^{-1}(x)) }

As the sin and inverse sin function do cancel each other, so only x² is left.

Hence,

y = \pm \sqrt{1-x^{2} ; -1\leq x\leq 1

<em>Keywords: trigonometric function </em>

<em>Learn more trigonometric function from brainly.com/question/12551115</em>

<em>#learnwithBrainly</em>

5 0
4 years ago
JG bisects FJH, FJG= (2x + 4)° and GJH = (3x -9)° <br> What is FJH
Kitty [74]

Hello from MrBillDoesMath!

Answer:

60

Discussion:

As JG bisects FJG,  

FJG     = GJH                =>

2x + 4 = 3x-9                => subtract 2x from each side

4         = 3x -2x - 9        => simplify

4         = x - 9                => add 9 to both sides

4 + 9   = x

x = 13

Now, FJH =

FJG        + GJH

(2x + 4)  + (3x-9) =

5x -5                             => substitute x 13

5(13) -5  =

65 - 5 =

60

Thank you,

MrB

5 0
3 years ago
Read 2 more answers
Find the absolute maximum value of the function (picture shown)
hammer [34]

Answer:

  1

Step-by-step explanation:

The maximum on the first interval is at x=0, where 2·0 +1 = 1.

The maximum on the second interval is near x=0, where the function value is near 0² +1 = 1.

The absolute maximum value of the function is 1.

3 0
4 years ago
You have at most $75 to spend on books and music. You want to spend less than $20 on music and no more than $60 on books. Which
Gemiola [76]

Answer:

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Step-by-step explanation:

7 0
3 years ago
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