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3 years ago

Which of the following is equivalent to 5√13^3?

1 answer:

3 0

LOL...it took me a few seconds to realize what you were attempting to express...which is the fifth root of 13 cubed...

(13^3)^(1/5) rule: (a^b)^c=a^(b*c)

13^(3*1/5)

13^(3/5)

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A right rectangular prism and a rectangular pyramid have the same base and height. How does the volume of the prism compare with

olga_2 [115]

Yeah he go it ..same base and height

8 0

3 years ago

The statistical difference between a process operating at a 5 sigma level and a process operating at a 6 sigma level is markedly

Svet_ta [14]

Answer:

True

Step-by-step explanation:

A six sigma level has a lower and upper specification limits between $\\ (\mu - 6\sigma)$ and $\\ (\mu + 6\sigma)$ . It means that the probability of finding no defects in a process is, considering 12 significant figures, for values symmetrically covered for standard deviations from the mean of a normal distribution:

$\\ p = F(\mu + 6\sigma) - F(\mu - 6\sigma) = 0.999999998027$

For those with defects operating at a 6 sigma level, the probability is:

$\\ 1 - p = 1 - 0.999999998027 = 0.000000001973$

Similarly, for finding no defects in a 5 sigma level, we have:

$\\ p = F(\mu + 5\sigma) - F(\mu - 5\sigma) = 0.999999426697$ .

The probability of defects is:

$\\ 1 - p = 1 - 0.999999426697 = 0.000000573303$

Well, the defects present in a six sigma level and a five sigma level are, respectively:

$\\ {6\sigma} = 0.000000001973 = 1.973 * 10^{-9} \approx \frac{2}{10^9} \approx \frac{2}{1000000000}$

$\\ {5\sigma} = 0.000000573303 = 5.73303 * 10^{-7} \approx \frac{6}{10^7} \approx \frac{6}{10000000}$

Then, comparing both fractions, we can confirm that a 6 sigma level is markedly different when it comes to the number of defects present:

$\\ {6\sigma} \approx \frac{2}{10^9}$ [1]

$\\ {5\sigma} \approx \frac{6}{10^7} = \frac{6}{10^7}*\frac{10^2}{10^2}=\frac{600}{10^9}$ [2]

Comparing [1] and [2], a six sigma process has 2 defects per billion opportunities, whereas a five sigma process has 600 defects per billion opportunities.

8 0

3 years ago

Blake and James are planning to go on a trip. Blake already has some money saved. She earns $96 more by working overtime. James

rosijanka [135]

Blake saved $\bold{\$ 433.80}$

Option - A

SOLUTION:

Given, Blake and James are planning to go on a trip.

Blake already has some money saved.

Let the amount saved by Blake be $\$ n$ .

She earns $\$96$ more by working overtime.

Then, total amount by Blake $=\$(n+96)$

James has $\$ 53$ more than 4 times the amount of money that Blake has saved.

Then, total amount by James will be $\$ 53+4 \times \$ n=\$(4 n+53)$

If they have $\$2,318$ in all, we have to find how much money had Blake originally saved

Now, total amount = $\$2318$

$\begin{array}{l}{\rightarrow \text { Amount by Blake }+\text { amount by James }=2318} \\\\ {\rightarrow \mathrm{n}+96+4 \mathrm{n}+53=2318 \rightarrow 5 \mathrm{n}+149=2318 \rightarrow 5 \mathrm{n}=2318-149 \rightarrow 5 \mathrm{n}=2169 \rightarrow \mathrm{n}=433.8}\end{array}$

7 0

3 years ago

Four congruent isosceles right triangles are cut from the 4 corners of a square with a side of 20 units. The length of one leg o

yanalaym [24]

Answer:

368 sq. units.

Step-by-step explanation:

We have a square of side lengths 20 units and we cut four congruent isosceles right triangles from the corners of the square.

Now, the four isosceles right triangles have one leg equal to 4 units.

Therefore, the area of four triangles = $4 \times ( \frac{1}{2} \times 4 \times 4) = 32$ sq. units.

Now, we have the area of the given square is (20 × 20) = 400 sq. units.

Therefore, the area of the remaining octagon will be (400 - 32) = 368 sq. units. (Answer)

7 0

3 years ago

3. Two quantities, x and y, are in a

frez [133]

Answer:

y = x + 1.8

Step-by-step explanation:

6 0

3 years ago