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Flura [38]
3 years ago
8

If 35 student are in student council, and 60% are boys. How many girls are in student council?

Mathematics
1 answer:
SSSSS [86.1K]3 years ago
4 0

40% are girls or more accurate would be 14

Solution:

What is 40% of 35?

Y is 40% of 35

Equation: Y = P% * X

Solving our equation for Y

Y = P% * X

Y = 40% * 35

Converting percent to decimal:

p = 40%/100 = 0.4

Y = 0.4 * 35

Y = 14

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The mean temperature for the first 4 days in January was 8°C. The mean temperature for the first 5 days in January was 7°C. What
mote1985 [20]

Answer:

The temperature of the 5th day was 3°C

Step-by-step explanation:

Mean temperature of the first 4 days = 8°C

Note that:

Mean = Sum of temperatures ÷ number of days

∴ 8 = sum of temperature ÷ 4

= 8 = \frac{sum\ of\ temperatures}{4}

= sum\ of\ temperatures\ = 8\ \times\ 4 = 32

Therefore the sum of the first 4 days = 32

Let the temperature of the next day (the fifth day) be m

Hence,

sum of the temperatures of first 5 days = 32 + m - - - - (1)

Next, the sum of the first 5 days can be calculated from the given average of the first 5 days as follows:

Mean temperature of the first 5 days = 7

Mean = \frac{sum\ of\ temperatures}{number \ of\ days}\\\\7 = \frac{sum\ of\ temperatures}{5} \\sum\ of\ temperatures\ = \ 7\ \times\ 5\ = 35\\sum\ of\ temperature\ of\ the\ first\ 5\ days\ =\ 35 - - - - - (2)

Now, you will notice that equation (1) = equation (2)

∴ 32 + m = 35

m = 35 - 32 = 3

therefore, the temperature of the 5th day was 3°C

4 0
3 years ago
How do I solve 3xy-2x= 17
butalik [34]
Let's solve for x.<span><span><span><span>3x</span>y</span>−<span>2x</span></span>=17
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6 0
3 years ago
What’s the vertex of f(x)=(x+5)^2
arlik [135]

Answer: (-5, 0)

Step-by-step explanation: The equation is already in completing the square form, a(x-h)^2 + k so you have both the x and y values for the vertex. Since there is no k here, the y value is 0.


6 0
3 years ago
Use the method in the Example to find the square roots of 1 + √3i
kiruha [24]

Answer:

\sqrt{1 + \sqrt{3} i}=\pm (1.58+i 0.548)

Step-by-step explanation:

Given

z = 1 + √3 i

Let \sqrt{1+\sqrt(3) i}=p+iq

Squaring both sides

1+\sqrt(3) i=p^2-q^2+2ipq

Comparing real and imaginary part

Re(LHS)=Re(RHS)

1=p^2-q^2...........................(1)

comparing Im(LHS)=Im(RHS)

√3=2pq

q=\frac{\sqrt{3}}{2p}

Substitute q in equation (1)

1=p^2-(\frac{\sqrt{3}}{2p})^2

p^4-p^2-0.75=0

Let x=p^2

x^2-x-0.75=0

x=\dfrac{1\pm \sqrt{1^2+4\times 0.75}}{2}

x=\frac{1\pm 4}{2}

we take only Positive value because p^2=x

x=2.5  

p^2=2.5

thus p=\pm 1.58

q=\pm 0.548

thus,

\sqrt{1 + \sqrt{3} i}=\pm (1.58+i 0.548)

5 0
3 years ago
Sifa has $156 in the bank. He needs to have at least $400 for spending money on his trip. Write and solve an inequality to find
gregori [183]
Sifa needs to earn $244

Solution
400-156=244

Therefore, He needs to earn $244 more before his trip.
6 0
2 years ago
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