Answer:
Given that an article suggests
that a Poisson process can be used to represent the occurrence of
structural loads over time. Suppose the mean time between occurrences of
loads is 0.4 year. a). How many loads can be expected to occur during a 4-year period? b). What is the probability that more than 11 loads occur during a
4-year period? c). How long must a time period be so that the probability of no loads
occurring during that period is at most 0.3?Part A:The number of loads that can be expected to occur during a 4-year period is given by:Part B:The expected value of the number of loads to occur during the 4-year period is 10 loads.This means that the mean is 10.The probability of a poisson distribution is given by where: k = 0, 1, 2, . . ., 11 and λ = 10.The probability that more than 11 loads occur during a
4-year period is given by:1 - [P(k = 0) + P(k = 1) + P(k = 2) + . . . + P(k = 11)]= 1 - [0.000045 + 0.000454 + 0.002270 + 0.007567 + 0.018917 + 0.037833 + 0.063055 + 0.090079 + 0.112599 + 0.125110+ 0.125110 + 0.113736]= 1 - 0.571665 = 0.428335 Therefore, the probability that more than eleven loads occur during a 4-year period is 0.4283Part C:The time period that must be so that the probability of no loads occurring during that period is at most 0.3 is obtained from the equation:Therefore, the time period that must be so that the probability of no loads
occurring during that period is at most 0.3 is given by: 3.3 years
Step-by-step explanation:
This is in slope-intercept form, so you can think of it as being y=mx+b. Invert m (the slope) and flip its sign, and then substitute the x and y values in and solve for b. The answer is y=7/2x-20.
Answer:
11 : 22 : 132
Step-by-step explanation:
1 + 2 + 12 = 15
165 ÷ 15 = 11
1 × 11 = 11
2 × 11 = 22
12 × 11 = 132
11 : 22 : 132
We are given D (7, -3) and D'(2, 5).
SAppy the transformation
D'(x,y) → D(x-5, y+8).
Then
x=7 → x=7-5 = 2
y=-3 → y=-3+8 = 5
Answer: D (x-5, y+8) → D'
Answer:
A. The relationship is proportional.
C. The slope is negative.
✓ A. The relationship is proportional.
-> We have a one to one proportion because the relationship is linear
✗ B. The slope is –6.
-> The slope is -3/2, not -3
-> We can pick a point, and then we count down 3 and over 2 to the next point
✓ C. The slope is negative.
-> Because the line is going from top left to bottom right the line is negative
✗ D. The y-intercept is –3.
-> The slope is -3/2, not -3
-> We can pick a point, and then we count down 3 and over 2 to the next point
✗ E. The equation of the line is y = –3x.
-> Again, the slope should be -3/2, not -3
Have a nice day!
I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)
- Heather