It would be A, most definitely.
Answer:
Probability that the proportion in our sample of red candies will be less than 20% is 0.5 .
Step-by-step explanation:
We are given that 20% of the candy produced are red. A random sample of 100 bags of Skittles is taken.
The distribution we can use here is;
~ N(0,1)
where, p = 0.20 and n = 100
Let
= proportion of red candies in our sample
So, P(
< 0.20) = P(
<
) = P(Z < 0) = 0.5
Therefore, probability that the proportion in our sample of red candies will be less than 20% is 0.5 .
I believe the equation is
![4 \sqrt[4]{2x} + 6 \sqrt[4]{2x}](https://tex.z-dn.net/?f=4%20%5Csqrt%5B4%5D%7B2x%7D%20%2B%206%20%20%5Csqrt%5B4%5D%7B2x%7D%20)
In this case, you would simplify it by adding them together.
![4 \sqrt[4]{2x} + 6 \sqrt[4]{2x}](https://tex.z-dn.net/?f=4%20%5Csqrt%5B4%5D%7B2x%7D%20%2B%206%20%20%5Csqrt%5B4%5D%7B2x%7D%20)
=
![10 \sqrt[4]{2x}](https://tex.z-dn.net/?f=10%20%20%5Csqrt%5B4%5D%7B2x%7D%20)
And can even be changed to an exponential equation:
Fraction- 24 357
-------
1000