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saveliy_v [14]
2 years ago
15

If p, q are zeroes of polynomial f(x) =2x^2-7x+3,find the value of p^2+q^2​

Mathematics
1 answer:
Elza [17]2 years ago
4 0

Answer:

p^2 + q^2 = 22/9.

Step-by-step explanation:

For a quadratic function ax^2 + bx + c if the zeroes are A and B then

A + B = -b/a and AB =  c/a.

2x^2 - 7x + 3

Now p and q are the zeroes of the above function so

p + q =  7/3 and pq = 3/2.

Now p^2 + q^2 = (p + q)^2 - 2pq

= (7/3)^2 - 2* 3/2

=  49/9 - 3

= 49/4 -  27/9

= 22/9.

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6 0
2 years ago
If price of 12 eggs is rs 192 , how many eggs can be bought for rs 160
Snowcat [4.5K]

Answer:

10 eggs

Step-by-step explanation:

We need to work out the price per unit :

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5 0
1 year ago
Read 2 more answers
The vertex of this parabola is at (-5,-2). when the x-value is -4, the y-value is 2. what is the coefficient of the squared expr
Westkost [7]
Vertex:  (-5,-2); parabola opens up; 

General form of the equation for a vertical parabola opening up is:

y-k = a(x-h)^2; knowing that the vertex is at (-5,-2), we can write:

y+2 = a(x+5)^2.  We need to find the value of the coefficient a.

From the graph we see that y is 10 when x is approx. -1 3/4 (or -7/4).

subst. these values into y+2 = a(x+5)^2, we get:

10 + 2 = a(-7/4 + 5)^2, or 12 = a(13/4)^2, or   1 = a(169/16).

Solving for a:  a = 16/169 = 0.09, or approx 16/160, or 1/10.  Unfortunately, this is not close to any of the four answer choices.

I thought it best to try again, and fortunately my second try was correct:

10+2 = a(13/4)^2, or  (169/16)a.  Thus, 12 = a(169/16)

                                   12
Solving for a:  a = ------------- = 1.14.  The answer choice closest to this is 1.
                                169/16

Answer A is correct.



6 0
3 years ago
Read 2 more answers
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