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saveliy_v [14]
2 years ago
15

If p, q are zeroes of polynomial f(x) =2x^2-7x+3,find the value of p^2+q^2​

Mathematics
1 answer:
Elza [17]2 years ago
4 0

Answer:

p^2 + q^2 = 22/9.

Step-by-step explanation:

For a quadratic function ax^2 + bx + c if the zeroes are A and B then

A + B = -b/a and AB =  c/a.

2x^2 - 7x + 3

Now p and q are the zeroes of the above function so

p + q =  7/3 and pq = 3/2.

Now p^2 + q^2 = (p + q)^2 - 2pq

= (7/3)^2 - 2* 3/2

=  49/9 - 3

= 49/4 -  27/9

= 22/9.

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A prime number less than 100 is selected randomly. what is the probability that its square has units digit $7$?
liberstina [14]
Any number ends with 0, 1, 2, 3, 4, 5, 6, 7, 8 or  9

Given any number. The square of this number is the last digit of square of the original numbers units digit.

For example

23*23 ends with 9 (3*3=9)

149*149 ends with 1 (9*9=81)

2564*2564 ends with 6 (4*4=16) 

and so on

so all the possible unit digits of a square number are {0, 1, 4, 5, 6, 9}

because:

0*0= 0 ; 1*1=1; 2*2=4; 3*3=9; 4*4=16; 5*5=25, 6*6=36; 7*7=49; 8*8=64, 9*9=81

Thus, the probability that the square of a number selected from any set of numbers being 7, is 0.


Answer: 0
 

4 0
3 years ago
PLZ HELP! ALL YOU NEED TO KNOW IS IN THE PICTURE!
Morgarella [4.7K]

Answer:

I can't cause u don't understand it too

7 0
3 years ago
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Goryan [66]

Answer:

700 or 960

Step-by-step explanation:

350x2=700

480x2=96

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3 years ago
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