It's a quadratic with a positive x² coefficient, so a CUP, with a minimum
f(x) = 2x² -12 x + 13 
= 2(x² - 6x) + 13 
= 2(x - 3)² - 2(9) + 13
f(x) = 2(x - 3)² - 5
Since x-3 is always zero or positive the least value is
f(3) = -5
Answer: -5
 
        
             
        
        
        
1. -36 
2. 30 
3. 5 
4. -5 
5. 1
        
                    
             
        
        
        
Which are the solutions of the quadratic equation?  
Given: x2 = 7x + 4
x2 = 7x + 4
0 = -x2 + 7x + 4
Answer:  x = (7 + √33) / 2
 
        
                    
             
        
        
        
Answer:
yes
Step-by-step explanation:
IBISHbPFIHBPFIHBFP
Yes