It's a quadratic with a positive x² coefficient, so a CUP, with a minimum
f(x) = 2x² -12 x + 13
= 2(x² - 6x) + 13
= 2(x - 3)² - 2(9) + 13
f(x) = 2(x - 3)² - 5
Since x-3 is always zero or positive the least value is
f(3) = -5
Answer: -5
1. -36
2. 30
3. 5
4. -5
5. 1
Which are the solutions of the quadratic equation?
Given: x2 = 7x + 4
x2 = 7x + 4
0 = -x2 + 7x + 4
Answer: x = (7 + √33) / 2
Answer:
yes
Step-by-step explanation:
IBISHbPFIHBPFIHBFP
Yes
