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3 years ago

What is the formula to finding the surface area of a triangular prism?

Mathematics

1 answer:

goblinko [34]3 years ago

6 0

Answer:

A=BxH 1/2

Step-by-step explanation:

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5.Simplify each of the following: (i) 7sqrt(2)+5sqrt(8) (ii) 15sqrt(6)-sqrt(216) (iii) 8sqrt(45)-8sqrt(20)+sqrt(245)-3sqrt(125)

emmainna [20.7K]

Answer:

(i) 17 $\sqrt{2}$

(ii) 9 $\sqrt{6}$

(iii) 0

Step-by-step explanation:

(i) 7 $\sqrt{2}$ + 5 $\sqrt{2}$ $\sqrt{4}$ = 7 $\sqrt{2}$ + 10 $\sqrt{2}$ = 17 $\sqrt{2}$

(ii) 15 $\sqrt{6}$ - $\sqrt{216}$ = 15 $\sqrt{6}$ - $\sqrt{36}$ · $\sqrt{6}$ = 9 $\sqrt{6}$

(iii) 8 $\sqrt{45}$ - 8 $\sqrt{20}$ + $\sqrt{245}$ - 3 $\sqrt{125}$ = 8 $\sqrt{9}$ · $\sqrt{5}$ - 8 $\sqrt{4}$ · $\sqrt{5}$ + $\sqrt{49}$ · $\sqrt{5}$ - 3 $\sqrt{25}$ · $\sqrt{5}$ =

24 $\sqrt{5}$ - 16 $\sqrt{5}$ + 7 $\sqrt{5}$ - 15 $\sqrt{5}$ = 8 $\sqrt{5}$ - 8 $\sqrt{5}$ = 0

8 0

3 years ago

I don’t understand it

Alisiya [41]

Let's deal with each factor in the numerator individually first: when evaluating the power of a power, you have to multiply the exponents: $(a^b)^c = a^{bc}$

So, we have

$[tex](3^2)^{-\frac{1}{2}} = 3^{2\cdot(-\frac{1}{2})} = 3^{-1},\quad (9^4)^{-1} = 9^{-4}$

Now remember that $9=3^2$ and $27=3^3$ to rewrite the expression as

$\dfrac{3^{-1}\cdot (3^2)^{-4}}{(3^3)^{-3}} = \dfrac{3^{-1}\cdot 3^{-8}}{3^{-9}}$

Now use the rules

$a^b\cdot a^c = a^{b+c},\quad \dfrac{a^b}{a^c} = a^{b-c}$

to conclude

$\dfrac{3^{-1}\cdot 3^{-8}}{3^{-9}} = 3^{-1-8-(-9) = 3^0 = 1$

7 0

3 years ago

Identify the 25th term of the arithmetic sequence 2, 1 and 3 over 5, <br> 1 and 1 over 5 …

maksim [4K]

We are given the arithmetic series 2, 1 3/5, 1 1/5.. In this case, the arithmetic difference is -2/5 by taking the difference of 2 and 1 3/5 and 1 3/5 and 1/5. The general formula of arithmetic sequence is an = a1 + d*(n-1). Substituting, an = 2 -2/5*(n-1). a25 hence is equal to a25 = 2-2/5*(25-1) = -38/5

8 0

3 years ago

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Lelechka [254]

Answer:

32 degrees. your welcome

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3 years ago

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scoray [572]