Brainly to fastest and correct answer,

Firdavs [7]

Answer:

x = 0

Step-by-step explanation:

The distributive property of multiplication states that a(b - c) = a(b) - a(c). We can apply that to the given equation.

3(2 - x) = 6

3(2) - 3(x) = 6 (Apply distributive property on LHS)

6 - 3x = 6 (Simplify LHS)

6 - 6 - 3x = 6 - 6 (Subtract 6 from both sides)

-3x = 0 (Simplify both sides)

$\frac{-3x}{-3} =\frac{0}{-3}$ (Divide both sides by -3)

x = 0 (Simplify)

Hope this helps!

8 0

4 years ago

A pharmaceutical company proposes a new drug treatment for alleviating symptoms of PMS (premenstrual syndrome). In the first sta

Akimi4 [234]

Answer:

95% confidence interval for p, the true proportion of all women who will find success with this new treatment is [0.238 , 0.762].

Step-by-step explanation:

We are given that a pharmaceutical company proposes a new drug treatment for alleviating symptoms of PMS (premenstrual syndrome).

In the first stages of a clinical trial, it was successful for 7 out of the 14 women.

Firstly, the pivotal quantity for 95% confidence interval for the true proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of women who find success with this new treatment = $\frac{7}{14}$ = 0.50

n = sample of women = 14

Here for constructing 95% confidence interval we have used One-sample z proportion statistics.

So, 95% confidence interval for the true proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5%

level of significance are -1.96 & 1.96}

P(-1.96 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

P( $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

95% confidence interval for p = [ $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.50-1.96 \times {\sqrt{\frac{0.50(1-0.50)}{14} } }$ , $0.50+1.96 \times {\sqrt{\frac{0.50(1-0.50)}{14} } }$ ]

= [0.238 , 0.762]

Therefore, 95% confidence interval for p, the true proportion of all women who will find success with this new treatment is [0.238 , 0.762].

4 0

4 years ago

Multiply the following fractions. 5/8 X 7/10 =

lubasha [3.4K]

The answer is 7/16 .

6 0

3 years ago

Read 2 more answers

At the beginning of an experiment, there are 400 grams of contaminants. Each hour, three-fourths of the contaminants are filtere

LiRa [457]

We have that

A).Formulate a recursive sequence modeling the number of grams after n hours.
a(n) = 0.75*a(n-1)

B) .Use the model to calculate the amount of contaminants after the third hour of the experiment.
 for the first hour
a(1) = 0.75*a(0)
a0=400 g
a1=(3/4)400 = 300 g

for the second hour
a(2) = 0.75*a(1)
a1=300 g
a2=(3/4)300 = 900/4 g

for the third hour
a(3) = 0.75*a(2)
a2=900/4 g
(3/4)900/4 = 2700/16 = 168.75 g

the answer is 168.75 g

8 0

3 years ago

Read 2 more answers

mr.barret bought a new battery for his new car. the battery cost $72. sincw batteries are a taxable item he had to pay 7.5%. wha

Aloiza [94]

$77.40

$72 (price) x 1.075 (the one is so you can do it in one step, the .075 is 7.5%)
That equals $77.40

8 0

3 years ago

Read 2 more answers