Answer:
8280 cal
Step-by-step explanation:
Q=mc(delta)T
Q=1200(0.115)(-60)
Q=8280 cal
I used 1200 g instead of 1.2 kg
Answer: 7
Step-by-step explanation: its correct, trust me
Using the information given above, the sampling distribution of the sample proportion of 100-ohm gold-band is 2.
- <em>Sampling distribution of proportion, P = 2% = 0.02 </em>
- <em>Sample size, n = 100</em>
<u>The sampling distribution of the sample proportion can be calculated thus</u>:
- <em>Distribution of sample proportion = np</em>
Distribution of sample proportion = (100 × 0.02) = 2
Therefore, there is a probability that only 2 of the samples will have resistances exceeding 105 ohms.
Learn more : brainly.com/question/18405415
Answer:
77
Step-by-step explanation:
HAV A GREAT DAY hope this helps
