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shtirl [24]
3 years ago
11

Solve each compound inequality (show your work!)

Mathematics
1 answer:
zimovet [89]3 years ago
4 0

Answer:  -1 < x < 8

                x = 3

                x ≠ 2

<u>Step-by-step explanation:</u>

Isolate x in the middle.  Perform operations to all 3 sides.

-6 < 2x - 4 < 12

<u>+4 </u>   <u>      +4</u>   <u>+4 </u>

-2 < 2x       < 16

<u>÷2  </u>  <u>÷2      </u>   <u> ÷2 </u>

-1   <   x       <  8

**************************************************************************

Isolate x.  Solve each inequality separately. Remember to flip the sign when dividing by a negative.

       4x ≤ 12       and       -7x ≤ 21

      <u>÷4  </u>  <u>÷4 </u>                 <u> ÷-7  </u>   <u>÷-7 </u>

        x ≤ 3         and         x ≥  3

Since it is an "and" statement, x is the intersection of both inequalities.

When is x ≤ 3 and ≥ 3?    <em>when x = 3</em>

****************************************************************************

Isolate x.  Solve each inequality separately.

    15x > 30       or           18x < -36

   <u>÷15 </u>  <u> ÷15 </u>                  <u> ÷18  </u>   <u>÷18 </u>

       x > 2          or              x <   2

Since it is an "or" statement, x is the union of both inequalities.

When we combine the inequalities, x is every value except 2.

x ≠ 2

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