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stepladder [879]
3 years ago
11

Describe the error Sadie made, and explain how to find the correct answer. (Refer to image)

Mathematics
2 answers:
seraphim [82]3 years ago
5 0
Sadie said that 54=3^3*6, which is false bacause 54=3^2*6. that's why she was wrong
radical 54a^7b^3=radical 3^2*6*a^6*a*b^2*b=3a^3b radical 6ab
ki77a [65]3 years ago
3 0

1. Sadie should note that 54a^7b^3\ge 0 and if a\ge 0, then b\ge 0.

2. While simplifying Sadie makes some mistakes (it must be 3^2 instead of 3^3 and she missed the sign of absolute value for b). The right way to find the correct answer is:

\sqrt{54a^7b^3}=\sqrt{3^2\cdot 6\cdot a^2\cdot a^5\cdot b^2\cdot b}  =3\cdot a\cdot |b| \sqrt{6\cdot a^5\cdot b}=3ab\sqrt{6a^5b}.

3. The simpliest expression is 3ab\sqrt{6a^5b} =3ab\sqrt{6\cdot a^2\cdot a^2\cdot a\cdot b} =3a^3b\sqrt{6ab}.

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Answer:

Hence proved that m∠AOD = m∠BCD.

Step-by-step explanation:

Given:

A Trapezoid with AC and BD as diagonals with O as intersection point to it.

Four angles formed at A and D are equal.

To Prove:

m∠AOD = m∠BCD

Proof:

Consider a Quadrilateral ABCD as trapezoid with diagonals as AC and BD

(Refer the Attachment).

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i.e. angle A=angle D

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Apply sum of all angles of triangle is 180.

And also

m∠2+∠AOD+m∠3=180

∠AOD=180-m∠2-m∠3..............equation(1)

And for Triangle BCD

m∠BCD=180-m∠3-m∠4,.....................Equation(2)

∠A=∠D................ as Quadrilateral is  Isosceles.

i.e.∠2=∠3

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Using this values in above equation(1) we get ,

∠AOD=180-∠3-∠4.......................(3)

Now comparing equation 2 and 3 we get

RHS is equal for both equation that means LHS is also equal .

Therefore ∠AOD=∠BCD

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