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stepladder [879]
3 years ago
11

Describe the error Sadie made, and explain how to find the correct answer. (Refer to image)

Mathematics
2 answers:
seraphim [82]3 years ago
5 0
Sadie said that 54=3^3*6, which is false bacause 54=3^2*6. that's why she was wrong
radical 54a^7b^3=radical 3^2*6*a^6*a*b^2*b=3a^3b radical 6ab
ki77a [65]3 years ago
3 0

1. Sadie should note that 54a^7b^3\ge 0 and if a\ge 0, then b\ge 0.

2. While simplifying Sadie makes some mistakes (it must be 3^2 instead of 3^3 and she missed the sign of absolute value for b). The right way to find the correct answer is:

\sqrt{54a^7b^3}=\sqrt{3^2\cdot 6\cdot a^2\cdot a^5\cdot b^2\cdot b}  =3\cdot a\cdot |b| \sqrt{6\cdot a^5\cdot b}=3ab\sqrt{6a^5b}.

3. The simpliest expression is 3ab\sqrt{6a^5b} =3ab\sqrt{6\cdot a^2\cdot a^2\cdot a\cdot b} =3a^3b\sqrt{6ab}.

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Step-by-step explanation:

Hello, please consider the following.

Using Maclaurin series expansion, we can find an equivalent of sin(x) in the neighbourhood of 0.

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Then,

\displaystyle \lim_{x\rightarrow0} \ {\dfrac{sin(4x)-4sin(x)}{x^3}}\\\\= \lim_{x\rightarrow0} \ {\dfrac{-10*x^3}{x^3}}\\\\=-10

Thank you

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