Answer:
15.21 %
Explanation:
If we recall the basic formula of Hardy-Weinberg's equilibrium ; we have the following below:
p + q = 1
p² + 2pq + q² = 1
where;
p = frequency of the dominant allele in the population
q = frequency of the recessive allele in the population
p² = percentage of homozygous dominant individuals
q² = percentage of homozygous recessive individuals
2pq = percentage of heterozygous individuals
Given that p= 0.68 and q = 0.39
the percentage of the homozygous recessive genotype (q² ) will be
(0.39)² = 0.1521
= 0.1521 × 100
= 15.21 %
∴ the percentage of the population that has a homozygous recessive genotype = 15.21 %
Brain tissue characterized by an intermixing of cell bodies and axons is called reticular <span>matter.</span>
Plants produce oxygen and glucose as a result of photosynthesis
I think the correct stage would be In the prophase.
Answer:
ATP synthase would be unable to produce ATP
Explanation:
ATP synthase depends on the proton gradient in the intermembrane space to enable it to produce ATP. As a consequence of this, the toxin will make it inactive. Oxidative phosphorylation is now inhibited in this case, as opposed to substrate-level phosphorylation.
Pyruvate is a product of glycolysis, and it will not be affected by a toxin. NADH is very important in the establishing of a proton gradient, so it is expected that it would be unable to be oxidized due to the toxin. Protons produced in the conversion of NADH to NAD+ actually establish the proton gradient. If the gradient is absent, NADH is then not likely to be oxidized.
