3/5 + 1/2 and can you please explain how to do it.

Mathematics

2 answers:

Anna11 [10]3 years ago

5 0

The simple way is cross multiplication
I will attach a paper you check it
brainliest pls

raketka [301]3 years ago

3 0

When adding fractions, you have to make sure the bottom numbers are the same. Otherwise, you can't add them.

So currently, the bottom number for the first fraction is 5. The bottom number for the second fraction is 2.

As you can see, 5 is not the same as 2, so we need to find one number to make sure the bottom number is the same for both the fractions.

You can multiply the the first fraction by 2, and the second fraction by 5 to give you two fractions that have the same denominator (bottom number.)

So, 3/5 multiplied by 2 is the same as multiplying 3 by 2, and 5 by 2. That gives you 6/10.

1/2 multiplied by 5 is 1 multiplied by 5, and 2 multiplied by 5, which is 5/10.

Now that you have your converted fractions, you can add them and forget about the bottom number, as it's the same. When adding fractions, if the bottom numbers are equal, you leave it as it is, so the 10 stays as 10:

6/10 + 5/10 = 11/10

Notice how I added 6 and 5 to give me 11, but I don't add 10 + 10, because I don't need to.

So the answer is 11/10.

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Mel randomly selects a coin 150 times selecting a dime 30 times, the experimental probability is 1/5 what is the theoretical pro

Stolb23 [73]

Answer:

Step-by-step explanation:

We can calculate probability by looking at the outcomes of an experiment or by reasoning What is the theoretical probability that a fair coin lands on heads? Choose 1 answer: Random numbers for experimental probability. This means that if we roll a die 60 times we can expect each of the six faces to come up.

Hope this helps.

Please give me brainliest if it is correct

6 0

3 years ago

A traffic light at a certain intersection is green 50% of the time, yellow 10% of the time, and red 40% of the time. A car appro

kati45 [8]

Answer:

$6.4\times 10^{-5} = 0.000064 = 0.0064\%$ .

Step-by-step explanation:

Probability that the car encounters a green light on the first day: $50 \% = 0.5$ .

To meet the question's conditions, the car needs to encounter another green light on the second day. Given that the colors of the light on each day are "independent," the chance that there's a green light followed by another green light will be

$(0.5) \times 0.5 = 0.25$ .

Condition is met on the first two days and green light on the third day: $(0.5 \times 0.5) \times 0.5 = 0.125$ .
Condition is met on the first three days and green light on the fourth day: $(0.5 \times 0.5 \times 0.5) \times 0.5$ .

To meet the condition on the fifth day, there needs to be a yellow light. The probability that the condition is met on the first four days and on the fifth day will be $(0.5 \times 0.5 \times 0.5 \times 0.5) \times 0.1 = 0.5^{4} \times 0.1$ .

To meet the condition on the sixth day, all prior days should meet the conditions. Besides, there needs to be a red light on the sixth day. $(0.5^{4} \times 0.1) \times 0.4$

Seventh day: $(0.5^{4} \times 0.1 \times 0.4 ) \times 0.4$
Eighth day: $(0.5^{4} \times 0.1 \times 0.4^2 ) \times 0.4$
Ninth day: $(0.5^{4} \times 0.1 \times 0.4^3 ) \times 0.4$
Tenth day: $(0.5^{4} \times 0.1 \times 0.4^4 ) \times 0.4 = 0.5^{4} \times 0.1 \times 0.4^{5}$

The question asks that the condition be met on all ten days. As a result, the probability of meeting the condition will be equal to the probability on the tenth day: $0.5^{4} \times 0.1 \times 0.4^{5} = 6.4\times 10^{-5} = 0.000064 = 0.0064\%$ .