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N76 [4]
3 years ago
5

Adults with more than a 12-month history of migraines were assigned randomly in a double-blinded study to receive treatment with

experimental drug X (10 or 20 mg/day) or placebo. The primary efficacy measure was the reduction in severity of the migraine attacks. Enrollment was 1,200 subjects. Which of the following best describes the clinical phase of this study?
Biology
1 answer:
lyudmila [28]3 years ago
5 0

Answer:

Phase III

Explanation:

The given condition fall in the trial phase (Phase III) of cinical study which aims to:

- Determine drug's effectiveness (primary goal)

- Determine long-term drug safety

- Confirm findings

In Phase III, randomised, double-blind, placebo-controlled, parallel group study is majorly to evaluate the efficacy and safety of placebo in episodic migraine prevention in children (6 to < 12 years of age) and adolescents (12 to < 18 years of age).  

The trial consists of four phases: screening; double-blind therapy period for 24 weeks in which placebo or Erenumab is given to subject as dose 1, dose 2 or dose 3 (based on the participant's body weight) once a month via subcutaneous injection; optional dose level blinded extension phase (40 weeks) which involves subjects recieve dose1, 2 and 3 of placebo, and at last it follows a safety follow-up phase for 12 weeks (after 16 weeks  of the last dose of investigational drug).

Hence, the clinical phase is phase III.

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At the end of the term, the professor locks the students in the classroom with plenty of food and water and leaves them there fo
levacccp [35]

Answer:

a. 0.7

b. 0.3

c. Yes

d. 90

Explanation:

As the random mating population was escaped from external evolutionary forces such as mutation, natural selection, and migration, the gene frequency will not change over time. The population will be at Hardy-Weinberg equilibrium throughout the time.

<u>As the number of sleepyheads (recessive trait) was 90 out of class of 1000 students at the start of course.</u>

<u />

q²=0.09 ∵ fraction of sleepyheads = 90/1000 = 0.09 denoted by q²

q that is the recessive gene frequency will be equal to 0.3 (by taking square root of P²

Hence, <em>allele frequency of a allele is 0.3</em>

<em></em>

As, frequency of dominant allele A is denoted by letter p and p+q=1

∴ p=0.7 As p=1-0.3

Hence,<em> allele frequency of A allele is 0.7</em>

<em></em>

Counting the probability of aa alleles (sleepyheads);

As a= 0.3

∴ aa= 0.3×0.3 = 0.09 (In terms of percentage, it is 9%)

To 0.09×1000= 90 or 9% of 1000 = 90

Hence, 90 students should be sleepyheads.

8 0
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