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2 years ago

7

Salvador is playing a game where the product must be greater than 2. Which two cards result in a product greater than 2? 1/2, 1

7/8, 8/9, 2/3, 5/4 *

1 answer:

Ivenika [448]2 years ago

6 0

Answer:

1 7/8 and 5/4

Step-by-step explanation:

when you multiply them together you get

2 11/32

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The question is incorrect because of the apparent contradiction the question makes.
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2 years ago

Measure the lengths of the sides of ∆ABC in GeoGebra, and compute the sine and the cosine of ∠A and ∠B. Verify your calculations

marusya05 [52]

Answer:

$Sin \angle A =0.80$

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Step-by-step explanation:

Given

I will answer this question using the attached triangle

Solving (a): Sine and Cosine A

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

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Substitute values for BC and BA

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$Sin \angle A =\frac{8}{10}$

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Substitute values for AC and BA

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$Cos \angle A=\frac{6}{10}$

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In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle B =\frac{AC}{BA}$

Substitute values for AC and BA

$Sin \angle B =\frac{6cm}{10cm}$

$Sin \angle B =\frac{6}{10}$

$Sin \angle B =0.60$

$Cos \angle B=\frac{BC}{BA}$

Substitute values for BC and BA

$Cos \angle B=\frac{8cm}{10cm}$

$Cos \angle B=\frac{8}{10}$

$Cos \angle B=0.80$

Using a calculator:

$A = 53^{\circ}$

So:

$Sin(53^{\circ}) =0.7986$

$Sin(53^{\circ}) =0.80$ -- approximated

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$Cos(53^{\circ}) = 0.60$ -- approximated

$B = 37^{\circ}$

So:

$Sin(37^{\circ}) = 0.6018$

$Sin(37^{\circ}) = 0.60$ --- approximated

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Read 2 more answers

I need help on number 2 through 9

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3 years ago