What are the domain and range of the function f(x) = 4?

Can someone help me PLEASE I've been trying to get someone to help me for hours Come on I'm offering 20 points?!?!?!?

Tom [10]

AND means multiply, so if probability is dependent on two things happening, then we will multiply the individual probabilities together.

1. P(A and 1) = 1/4 x 1/6 = 1/24

2. P(C and 2) = 1/4 x 2/6 = 2/24 = 1/12

3. P(B and 3) = 2/4 x 1/6 = 2/24 = 1/12

4. P(A and 4) = 1/4 x 2/6 = 2/24 = 1/12

5. P(C and 3) = 1/4 x 1/6 = 1/24

6. P(B and 2) = 2/4 x 2/6 = 4/24 = 1/6

7. P(a consonant and an odd #) = 3/4 x 2/6 = 6/24 = 1/4

8. P(a consonant and a prime #) = 3/4 x 3/6 = 9/24 = 3/8

9. P(a vowel and a 5) = 1/4 x 0/6 = 0

10. P(a vowel and a number less than 3) = 1/4 x 3/6 = 3/24 = 1/8

11. P(B and 1) = 2/4 x 1/6 = 2/24 = 1/12

Experimental probability is based on something that has already happened, or data that has already been collected.

12. P(1) = 3/30 = 1/10

13. P(2) = 8/30 = 4/15

14. P(3) = 7/30

15. P(4) = 5/30 = 1/6

16. P(5) = 3/30 = 1/10

17. P(6) = 4/30 = 2/15

Hope this helps!

4 0

2 years ago

Pls help with this question

andre [41]

Answer:

x<56

Step-by-step explanation:

Since the dot over 56 isn't filled in, the inequality doesn't include 56 (so we'll use < or > not $\leq$ or $\geq$ )

Now, let's look at the direction of the shading: is it going to the left of 56 or to the right?

This shading is to the left of 56, which indicates that it's all of the numbers less than 56.

As said above, the inequality doesn't include 56

therefore, it will be x<56 (x is less than 56, and 56 is not included)

hope this helps!

3 0

3 years ago

Read 2 more answers

Ruby is visiting a wildlife center to gather information for her term paper. The center has a circular pond with a diameter of 2

kicyunya [14]

C, since the radius is 10 multiply by 2 and 100 x 3.14 is 314

5 0

3 years ago

Read 2 more answers

What Val are restricted from the domain of

djverab [1.8K]

<u>Given</u>:

The given expression is $\frac{\left(4 x^{2}-4 x+1\right)}{(2 x-1)^{2}}$

We need to determine the values for which the domain is restricted.

<u>Restricted values:</u>

Let us determine the values restricted from the domain.

To determine the restricted values from the domain, let us set the denominator the function not equal to zero.

Thus, we have;

$(2x-1)^2\neq 0$

Taking square root on both sides, we get;

$2x-1\neq 0$

$2x\neq 1$

$x\neq \frac{1}{2}$

Thus, the restricted value from the domain is $x\neq \frac{1}{2}$

Hence, Option A is the correct answer.

7 0

3 years ago

URGENT: If θ is a second-quadrant angle and cosθ = -2/3, then tanθ = _____.

dangina [55]

In the second quadrant, both cos and tan are negative while only sin is positive.

To find tan, we will use the following property below:

$\large \boxed{ {tan}^{2} \theta = {sec}^{2} \theta - 1}$

Sec is the reciprocal of cos. If cos is a/b then sec is b/a. Since cos is 2/3 then sec is 3/2

$\large{ {tan}^{2} \theta = {( - \frac{3}{2}) }^{2} - 1} \\ \large{ {tan}^{2} \theta = \frac{9}{4} - 1} \\ \large{ {tan}^{2} \theta = \frac{9}{4} - \frac{4}{4} \longrightarrow \frac{5}{4} } \\ \large{tan \theta = \frac{ \sqrt{5} }{ \sqrt{4} } } \\ \large \boxed{tan \theta = \frac{ \sqrt{5} }{2} }$

Since tan is negative in the second quadrant. Hence,

$\large{ \cancel{ tan \theta = \frac{ \sqrt{5} }{2} } \longrightarrow \boxed{tan \theta = - \frac{ \sqrt{5} }{2} }}$

Answer

tan = -√5/2

3 0

2 years ago