<span>First we have to determine the slope of each lines by transforming to the slope-intercept form:
y=(3x-7/)4; m2= ¾y=(12x+6)/5, m3 = 12/5
The formula to be used in the proceeding steps is a=tan^-1(m1-m2)/1+m1m2=tan^-1(m1-m2)/1+m1m2
substituting, a=tan^-1(m1-3/4)/1+3m1/4=tan^-1(m1-12/5)1+12m1/5) =>(4m1-3)/(4+3m1)=(5m1-12)/(5+12m1)m1 = -1applying this slope
y -y1 = m(x-x1)
when y1 = 5 and x1 = 4 then,
y - 5 = -1(x-4)
y = -x +4+ 5 ; y = -x +9</span>
It would be better to buy 16 oz for 2.88.
Why?: 12 oz for 2.15, it would cost roughly 5.58. And 16 oz for 2.88 cost 5.55 per. So, it's 3 cents cheaper per.
Let me know if this helps! Have a great day!
Answer:
She uses 243 beads for the 5th string.
Step-by-step explanation:
In this problem, we can see a pattern. If she triples the number of beads in each of the next strings, that means that we just take the last number and multiply by 3. If the first string uses 3, then:
The second uses 9, 3 * 3 = 9
The third uses 27, 9 * 3 = 27
The fourth uses 81, 27 * 3 = 81
And the 5th uses 243, 81 * 3 = 243.
Our current list has 11!/2!11!/2! arrangements which we must divide into equivalence classes just as before, only this time the classes contain arrangements where only the two As are arranged, following this logic requires us to divide by arrangement of the 2 As giving (11!/2!)/2!=11!/(2!2)(11!/2!)/2!=11!/(2!2).
Repeating the process one last time for equivalence classes for arrangements of only T's leads us to divide the list once again by 2