The number of ways to select 4 digits from 10 digits is
₁₀C₄ = 10!/(4!*6!)
= (10*9*8*7*6!)/(4*3*2*1*6!)
= (10*9*8*7)/(4*3*2)
= 210
If order is not important, the number of arrangements of 6,7,8,9 in any order is
4! = 4*3*2*1
= 24
The probability that these 4 digits are assigned is
24/210 = 0.1143
Answer:
Strong, negative and linear association
A counterexample could be -2.
-2+-2= -4
-4<-2
Hope this helps!