Sasha does push-ups each day for five days. The numbers of push-ups she does each day or shown below.
1 answer:
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I'm going to assume the crust covered by the dosenot matter because the total surface area cannot be found without the depth of the pie.
So the surface are is the area of the top of the pie, the top of the pie is circular and is equal to 2
r²
The diameter is the sum of 2 radii, hence r=8
D=12
= 2r =12
r=8
With the raduis the area can be found
A= 2r²
A=28²
A=2(64)
A=128
If the pie cost 10.99, the cost per inch can be found by dividing the area by cost
cost/inch =128/10.99
cost/inch =11.64
= 11.64(3.14)
= 36.57
The pie costs 36 cents per square inch
So the surface are is the area of the top of the pie, the top of the pie is circular and is equal to 2
The diameter is the sum of 2 radii, hence r=8
D=12
= 2r =12
r=8
With the raduis the area can be found
A= 2
A=2
A=2(64)
A=128
If the pie cost 10.99, the cost per inch can be found by dividing the area by cost
cost/inch =128
cost/inch =11.64
= 11.64(3.14)
= 36.57
The pie costs 36 cents per square inch
Answer with Step-by-step explanation:
1. We are given that an expression
We have to prove that this expression is always is even for every integer.
There are two cases
1.n is odd integer
2.n is even integer
1.n is an odd positive integer
n square is also odd integer and n is odd .The sum of two odd integers is always even.
When is negative odd integer then n square is positive odd integer and n is negative odd integer.We know that difference of two odd integers is always even integer.Therefore, given expression is always even .
2.When n is even positive integer
Then n square is always positive even integer and n is positive integer .The sum of two even integers is always even.Hence, given expression is always even when n is even positive integer.
When n is negative even integer
n square is always positive even integer and n is even negative integer .The difference of two even integers is always even integer.
Hence, the given expression is always even for every integer.
2.By mathematical induction
Suppose n=1 then n= substituting in the given expression
1+1=2 =Even integer
Hence, it is true for n=1
Suppose it is true for n=k
then is even integer
We shall prove that it is true for n=k+1
=
=
=Even +2(k+1)[/tex] because is even
=Sum is even because sum even numbers is also even
Hence, the given expression is always even for every integer n.