Think: To write the equation of a line in slope-intercept form y=mx+b, you must have the slope (m) and the y-intercept (b).
g(0)= -6 tells us that the y-intercept is (0, -6). Thus, b= -6.
(0,-6) and (15,-9) are points on the line. Find the slope of the line. It is:
-9-(-6)
m = ------------- = -3/15 = -1/5
15-0
Thus, the equation of the line in question is y=(-1/5)x - 6.
Important that you understand that g(0)=-6 is also represented by (0,-6), and that -6 is the y-intercept.
Answer:
x = 15
Step-by-step explanation:
Given
See attachment
Required
Find x
The figure in the attachment is a quadrilateral and the angles in a quadrilateral add up to 360.
So, we have:
90 + 6x + 5+ 10x - 40 + 4x + 5 = 360
Collect like terms
6x + 10x + 4x = 360 - 90 - 5 + 40 - 5
20x = 300
Divide both sides by 20
x = 15
Hence, the value of x is 15
Answer:
6
Step-by-step explanation:
2x + 7 = 19
-7 -7
2x = 12
12/2 = x
6 = x
Answer:
0.08065
Step-by-step explanation:
Given that in a recent study,1 2006 randomly selected US adults (age 18 or older) were asked to give the number of people in the last six months with whom you discussed matters that are important to you.
If X is random variable then X has mean 2.2 and s = 1.4
n=2006
Std error of mean =
For 99% since sample size is large, t and z distn almost coincide.
Hence we can take 2.58 as critical value
Margin of error at 99% =
Hello there! Given there are 70 employees after downsizing by 30%, let x equal the number of employees prior to the layoffs:
70 would have to be 70% of x.
To find what 70 is 70% of, we can multiply by 100 because 100 is the base denominator:
70 • 100 = 7,000
Given this equation, we can now divide our result by 70 to get what the amount of employees before the layoffs is:
7,000 divided by 70 gives us 100.
x = 100
Now, we can plug our answer in to see if it makes sense.
Does 70/100 represent 70%?
Yes, it does. 70/100 reduces to 7/10, and by adding 3/10 to our 70%, we get the initial amount of employees.
Your final answer: There were 100 employees prior to the layoffs. If you have any extra questions, let me know and I will gladly assist you.
