Answer:
(9/5, 8/5)
Step-by-step explanation:
First you want to find the equations of the lines. One line is y = 2x - 2 and the other line is y = 1/3x + 1. Then you want to find the x and y that both work in the two equations.
y = 2x - 2
y = 1/3x + 1
Then you do 2x - 2 = 1/3x + 1
Then you do some maths and you get 9/5, and 8/5
Answer:
Algebra
Topics
How do you find the intercepts of x2y−x2+4y=0?
Algebra Graphs of Linear Equations and Functions Intercepts by Substitution
2 Answers
Gió
Mar 24, 2015
For the intercepts you set alternately x=0 and y=0 in your function:
and graphically:
Answer link
Alan P.
Mar 24, 2015
On the X-axis y=0
So
x2y−x2+4y=0
becomes
x2(0)−x2+4(0)=0
→−x2=0
→x=0
On the Y-axis x=0
and the original equation
x2y−x2+4y=0
becomes
(0)2y−(0)2+4y=0
→y=0
The only intercept for the given equation occurs at (0,0)
Answer link
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Answer:
Step-by-step explanation:
1.
Equation one:
x = -5, x = -1 (Both are real)
Equation two:
No real solutions
Equation three:
x = -3 (Real)
Equation four:
No real solutions
2.
The easiest way to figure out if an equation has real solutions is to factor it. If it is factorable, then it has real solutions. If it isn't, then it doesn't have real solutions.
Answer:10
Step-by-step explanation:
1.
so
Answers B and D.
2.
Answer D.
3.
The same as point 2. Answer D.
4.
Answer C.
