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Anestetic [448]

3 years ago

14

Can someone help thanks

1 answer:

Salsk061 [2.6K]3 years ago

4 0

The equation for the volume of a pyramid is (l*w*h)/3

since the problem gave you the base area, that would be the l *w

so now you would need to multiply the base area by the height, then divide by 3

16 * 15 = 240

240/ = 80 cubic centimeters

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Name two pairs of adjacent angels and two pairs of vertical angels in figure

sashaice [31]

Answer:

As in this case where the adjacent angles are formed by two lines intersecting we will get two pairs of adjacent angles (G + F and H + E) that are both supplementary. Two angles that are opposite each other as D and B in the figure above are called vertical angles. Vertical angles are always congruent

Step-by-step explanation:

3 0

3 years ago

What is the name of the line of reflection for the pair of figures? Enter your answer in the box. line

statuscvo [17]

Are you asking for the letter or what the line is called because if it's just the letter then it is r if it is the name then its a plane intersect.

7 0

3 years ago

Read 2 more answers

olchik [2.2K]

$3996 \times \frac{1}{3} = 1332$
the volume is 1332 in^3

good luck

4 0

3 years ago

For the function y=3x2: (a) Find the average rate of change of y with respect to x over the interval [3,6]. (b) Find the instant

nirvana33 [79]

Answer:

The instantaneous rate of change of $y$ with respect to $x$ at the value $x = 3$ is 18.

Step-by-step explanation:

a) Geometrically speaking, the average rate of change of $y$ with respect to $x$ over the interval by definition of secant line:

$r = \frac{y(b) -y(a)}{b-a}$ (1)

Where:

$a$ , $b$ - Lower and upper bounds of the interval.

$y(a)$ , $y(b)$ - Function exaluated at lower and upper bounds of the interval.

If we know that $y = 3\cdot x^{2}$ , $a = 3$ and $b = 6$ , then the average rate of change of $y$ with respect to $x$ over the interval is:

$r = \frac{3\cdot (6)^{2}-3\cdot (3)^{2}}{6-3}$

$r = 27$

The average rate of change of $y$ with respect to $x$ over the interval $[3,6]$ is 27.

b) The instantaneous rate of change can be determined by the following definition:

$y' = \lim_{h \to 0}\frac{y(x+h)-y(x)}{h}$ (2)

Where:

$h$ - Change rate.

$y(x)$ , $y(x+h)$ - Function evaluated at $x$ and $x+h$ .

If we know that $x = 3$ and $y = 3\cdot x^{2}$ , then the instantaneous rate of change of $y$ with respect to $x$ is:

$y' = \lim_{h \to 0} \frac{3\cdot (x+h)^{2}-3\cdot x^{2}}{h}$

$y' = 3\cdot \lim_{h \to 0} \frac{(x+h)^{2}-x^{2}}{h}$

$y' = 3\cdot \lim_{h \to 0} \frac{2\cdot h\cdot x +h^{2}}{h}$

$y' = 6\cdot \lim_{h \to 0} x +3\cdot \lim_{h \to 0} h$

$y' = 6\cdot x$

$y' = 6\cdot (3)$

$y' = 18$

The instantaneous rate of change of $y$ with respect to $x$ at the value $x = 3$ is 18.

5 0

3 years ago

Write each decimal as a fraction or mixed numbest form. -7.08

Andreas93 [3]

-(7+8/100)
= -(7+4/50)
= -(7+2/25)
= -177/25

7 0

3 years ago