Answer:10
Step-by-step explanation:
2+4+6+6+9+13+30=70
70 divided by 7= the mean should be 10
Answer:
The percentage of the bag that should have popped 96 kernels or more is 2.1%.
Step-by-step explanation:
The random variable <em>X</em> can be defined as the number of popcorn kernels that popped out of a mini bag.
The mean is, <em>μ</em> = 72 and the standard deviation is, <em>σ</em> = 12.
Assume that the population of the number of popcorn kernels that popped out of a mini bag follows a Normal distribution.
Compute the probability that a bag popped 96 kernels or more as follows:
Apply continuity correction:


*Use a <em>z</em>-table.
The probability that a bag popped 96 kernels or more is 0.021.
The percentage is, 0.021 × 100 = 2.1%.
Thus, the percentage of the bag that should have popped 96 kernels or more is 2.1%.
Answer:
17
Step-by-step explanation:
Number of students in soccer club, n(S) = 50
Number of students in Art club, n(A) = 53
Number of students in Gaming club, n(G)
n(
) = 100
n(
) = 9
n(
) = 20
n(
) = 35
n(
) = 29
Formula:
n ( A ∪ B ∪ C ) = n(A) + n(B) + n(C) – n ( A ∩ B ) – n(B ∩ C) – n (A ∩ C) + n( A ∩ B ∩ C )
Putting the values:
100 = 50 + 53 + n(G) - 20 - 35 - 29 + 9
100 = 112 + n(G) - 84
n(G) = 72
Number of students in gaming club only = n(G) - n(
) - n(
) + n(
)
= 72 - 35 - 29 + 9
= <em>17</em>
Answer:
x > - 3
Step-by-step explanation:
Given
3(x + 2) > x ← distribute left side
3x + 6 > x ( subtract x from both sides )
2x + 6 > 0 ( subtract 6 from both sides )
2x > - 6 ( divide both sides by 2 )
x > - 3