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AlekseyPX
3 years ago
15

There are 25 students in Ms. Morris's class.She wants to divide the class into 3,4,or 5 equal teams.Which number of teams can sh

e have?explain
Mathematics
1 answer:
olga nikolaevna [1]3 years ago
6 0
If there are 25 students and she wants either 3,4,5 equal teams you simply take and divide 25 by the numbers and determine if they are equal teams or not. So dividing 25 by 3 and getting 8.3 repeating isn't an equal team which means she cant have only 3 teams. Or you can divide 25 by 4 which will give you 5 students to a group which is an equal team set through out the room, also you can divide 25 by 5 which gives you 4 students to a group which also is an equal team set through out the room. Therefore the numbers of groups she can have are 4 and 5 but 3 is out of the question because it is a decimal also another thing about it is that it's an irrational number. 
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Answer:10

Step-by-step explanation:

2+4+6+6+9+13+30=70

70 divided by 7= the mean should be 10

6 0
2 years ago
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A researcher was testing the number of popcorn kernels that popped out of a mini bag of 100 kernels after being cooked for the s
Lelechka [254]

Answer:

The percentage of the bag that should have popped 96 kernels or more is 2.1%.

Step-by-step explanation:

The random variable <em>X</em> can be defined as the number of popcorn kernels that popped out of a mini bag.

The mean is, <em>μ</em> = 72 and the standard deviation is, <em>σ</em> = 12.

Assume that the population of the number of popcorn kernels that popped out of a mini bag follows a Normal distribution.

Compute the probability that a bag popped 96 kernels or more as follows:

Apply continuity correction:

P( X\geq 96)=P( X>96+0.50)

                 =P( X>96.50)\\=P(\frac{X-\mu}{\sigma}>\frac{96.50-72}{12})\\=P(Z>2.04)\\=1-P(Z

*Use a <em>z</em>-table.

The probability that a bag popped 96 kernels or more is 0.021.

The percentage is, 0.021 × 100 = 2.1%.

Thus, the percentage of the bag that should have popped 96 kernels or more is 2.1%.

3 0
3 years ago
At Prairieview Middle School, 100 students participate in at least one of three after-school clubs: soccer club, art club, and g
Tresset [83]

Answer:

17

Step-by-step explanation:

Number of students in soccer club, n(S) = 50

Number of students in Art club, n(A) = 53

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n(S \cup A\cup G) = 100

n(S \cap A\cap G) = 9

n(S \cap A) = 20

n(A \cap G) = 35

n(G \cap S) = 29

Formula:

n ( A ∪ B ∪ C ) =  n(A) + n(B) + n(C) – n ( A ∩ B ) – n(B ∩ C) – n (A ∩ C) + n( A ∩ B ∩ C )

Putting the values:

100 = 50 + 53 + n(G) - 20 - 35 - 29 + 9

100 = 112 + n(G) - 84

n(G) = 72

Number of students in gaming club only = n(G) - n(G \cap S) - n(A \cap G) + n(S \cap A\cap G)

= 72 - 35 - 29 + 9

= <em>17</em>

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MaRussiya [10]

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