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3 years ago

What is 6/5 x 25/24 = ?

Mathematics

2 answers:

Margaret [11]3 years ago

5 0

The answer is 5/4 or 1 and 1/4 (both answers are correct just different forms), hope this helps !

serg [7]3 years ago

5 0

To find the answer you just multiply straight across so 6 times 25 = 150 and 5 times 24= 120.

then you need to divide 150/120 = 1.25

other forms would be 5/4, 1.25, and 1 1/4. hope this helps!

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Trina has $1000 to purchase an open-top cylindrical dog pen in her backyard. She wants the height of the pen to be 5 feet. If th

RideAnS [48]

Answer:

C. 31.83 feet.

Step-by-step explanation:

We have been given that Trina has $1000 to purchase an open-top cylindrical dog pen in her backyard. She wants the height of the pen to be 5 feet.

First of all, we will find the surface area of dog pen using surface area of cylinder.

$\text{Surface area of cylinder}=2\pi rh$ ,where,

r = Radius of cylinder,

h = Height of cylinder.

$\text{Surface area of cylinder}=2\pi r*5$

$\text{Surface area of cylinder}=10\pi r$

Since the area of each square foot of pen costs $1, so in $1000 Trina can cover an area of 1000 square feet.

Now, we will set the surface area of cylinder equal to 1000 to solve for the radius.

$1000=10\pi r$

Upon dividing both sides of our equation by 10 pi we will get,

$\frac{1000}{10\pi}=\frac{10\pi r}{10\pi}$

$31.8309886=r$

$r\approx 31.83$

Therefore, the radius of the dog pen is 31.83 feet and option C is the correct choice.

4 0

3 years ago

A representative from the National Football League's Marketing Division randomly selects people on a random street in Kansas Cit

Orlov [11]

Using the binomial distribution, we have that:

a) 0.1024 = 10.24% probability that the marketing representative must select 4 people to find one who attended the last home football game.

b) 0.2621 = 26.21% probability that the marketing representative must select more than 6 people to find one who attended the last home football game.

c) The expected number of people is 4, with a variance of 20.

For each person, there are only two possible outcomes. Either they attended a game, or they did not. The probability of a person attending a game is independent of any other person, which means that the binomial distribution is used.

Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

p is the probability of a success on a single trial.

n is the number of trials.

p is the probability of a success on a single trial.

The expected number of <u>trials before q successes</u> is given by:

$E = \frac{q(1-p)}{p}$

The variance is:

$V = \frac{q(1-p)}{p^2}$

In this problem, 0.2 probability of a finding a person who attended the last football game, thus $p = 0.2$ .

Item a:

None of the first three attended, which is P(X = 0) when n = 3.
Fourth attended, with 0.2 probability.

Thus:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{3,0}.(0.2)^{0}.(0.8)^{3} = 0.512$

$0.2(0.512) = 0.1024$

0.1024 = 10.24% probability that the marketing representative must select 4 people to find one who attended the last home football game.

Item b:

This is the probability that none of the first six went, which is P(X = 0) when n = 6.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{6,0}.(0.2)^{0}.(0.8)^{6} = 0.2621$

0.2621 = 26.21% probability that the marketing representative must select more than 6 people to find one who attended the last home football game.

Item c:

One person, thus $q = 1$ .

The expected value is:

$E = \frac{q(1-p)}{p} = \frac{0.8}{0.2} = 4$

The variance is:

$V = \frac{0.8}{0.04} = 20$

The expected number of people is 4, with a variance of 20.

A similar problem is given at brainly.com/question/24756209

3 0

2 years ago

In order to clear out room for new merchandise, James decided to mark down some of the items for sale in his electronics store.

sergiy2304 [10]

Answer:

a) Which item’s price was reduced by more, and by how many dollars more was it reduced?

The DVD player's price was reduced more by $3.82 than the stereo tuner's price.

b) Round all dollar values to the nearest cent.

Rounding $3.82 dollars to the nearest cents

$1 = 100 cents

$3.82 =

3.82 × 100 cents

= 382 cents

The DVD player's price was reduced by 382 cents more than the stereo tuner's price

Step-by-step explanation:

Lets day the original price of the DVD player was $100

We are told the price was marked down to 36%

36% of $100 = $36

$100 - $36 = $64

We are told the DVD cost $41.60 after the markdown.

Original cost of DVD =

$41.60/$64 × 100 = $65

Lets the original price of the Stereo player was $100

We are told the price was marked down to 22%

22% of $100 = $22

$100 - $22 = $78

We are told the DVD cost $69.42 after the markdown.

Original cost of Stereo =

$69.42/$78 × 100 = $89

DVD = $65 - $41.60 = $23.40 less

Stereo = $89 - 69.42 = $19.58 less

Difference between the DVD and the Stereo is

$23.40 - $19.58 = $3.82

Therefore,the DVD player's price was reduced by $3.82 more than the stereo tuner's price

Rounding $3.82 dollars to the nearest cents

$1 = 100 cents

$3.82 =

3.82 × 100 cents

= 382 cents

8 0

3 years ago

Read 2 more answers

A bag contains a variety of different colored marbles. P( red)= 1/2, P( green) = 1/4, and P( red and green) = 1/8 , which statem

Veronika [31]

Answer:

Step-by-step explanation:

The 1 choice. The events are independent because P(red) ×P(green)= P(red and green)

6 0

3 years ago

Read 2 more answers

A quadrilateral WXYZ has vertices W(3, −5), X(1, −3), Y(−1, −5), and Z(1,−7). What are the vertices of r(90, O)(WXYZ)?

VashaNatasha [74]

Given:

A quadrilateral WXYZ has vertices W(3, −5), X(1, −3), Y(−1, −5), and Z(1,−7).

Rule of rotation is $r_{(90^\circ, O)}(WXYZ)$ .

To find:

The vertices after rotation.

Solution:

We know that, $r_{(90^\circ, O)}(WXYZ)$ means 90 degrees counterclockwise rotation around the origin.

So, the rule of rotation is defined as

$(x,y)\to (-y,x)$

Using this rule, we get

$W(3,-5)\to W'(5,3)$

$X(1,-3)\to X'(3,1)$

$Y(-1,-5)\to Y'(5,-1)$

$Z(1,-7)\to Z'(7,1)$

Therefore, the required vertices after rotation are W'(5,3), X'(3,1),Y'(5,-1) and Z'(7,1).

8 0

3 years ago