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3 years ago

11

Zina solves a system of linear equations by elimination and finds a solution of (2, 2). One of the equations is a + b = 4. What

is the other equation?

2 answers:

Dima020 [189]3 years ago

6 0

Answer:

Option D

a+3b=8

MA_775_DIABLO [31]3 years ago

3 0

Answer:

D is correct

Step-by-step explanation:

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Hallie bikes 1 5/8 km before lunch and 6 1/4 km after lunch. How much farther does Hallie bike after lunch than before lunch? Ex

EleoNora [17]

Answer:

4 $\frac{5}{8}$ km

Step-by-step explanation:

To find how much farther Hallie biked after lunch compared to the amount she biked before lunch, we can subtract the amounts:

6 $\frac{1}{4}-1\frac{5}{8}$

However, we can only subtract fractions that have the same denominator, so we need to convert $\frac{1}{4}$ to a fraction with a denominator of 8:

$\frac{1}{4}=\frac{2}{8}$

Now, we can't subtract 2 from 8, so we need to 'borrow' from the 6 to make the fraction larger:

$6\frac{2}{8}=5\frac{10}{8}$

Now subtract: $5\frac{10}{8}-1\frac{5}{8}=4\frac{5}{8}$

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3 years ago

A food pantry is making packages. each package weights 64 pounds. Here are two situations. for each situation, write and solve a

alexdok [17]

Answer:

Step-by-step explanation:

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2 years ago

Which of the following values are solutions to the inequality -5 -6x > -8?

kati45 [8]

The answer is :x< 1/2

6 0

1 year ago

Read 2 more answers

Victors car is 120 inches long Alison’s car is 5 yards long when you line them up in front of the other how long are they in fee

hichkok12 [17]

Answer:

25ft

Step-by-step explanation:

12 inches = 1 ft. Hence,

120 inches = 10 ft.

Likewise,

1 yard = 3 ft

5 yards = 15 ft

Hence, the length of both cars together is,

10 ft + 15 ft = 25 ft

8 0

2 years ago

The altitude of a triangle is 2 m longer than its base. What are the dimensions of the altitude and the base if thearea of the t

HACTEHA [7]

Step-by-step explanation:

Let base of triangle be x m.

Therefore, altitude =( x + 2)m

$area \: of \: \triangle = \frac{1}{2} \times base \times altitude \\ \\ 40 = \frac{1}{2} \times x \times (x + 2) \\ \\ 80 = {x }^{2} +2x \\ \\ {x}^{2} + 2x - 80 = 0 \\ {x}^{2} + 10x - 8x - 80 \\ x(x + 10) - 8(x + 10) = 0\\ (x + 10)(x - 8) = 0 \\ x + 10 = 0 \: \: or \: \: x - 8 = 0 \\ x = - 10 \: \: or \: \: x = 8 \\ base \: can \: not \: be \: - ve \\ x \neq - 10 \\ x = 8 \\ x + 2 = 8 + 2 = 10 \\$

Therefore

Altitude = 10 m

Base = 8 m

8 0

3 years ago