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k0ka [10]
3 years ago
15

How would you find the surface area of a cube, if you knew the area of one face ???

Mathematics
2 answers:
Nataly_w [17]3 years ago
8 0

Answer:

<h2>Step-by-step </h2>
alexandr402 [8]3 years ago
8 0

Answer:

just times the area by 6!

Step-by-step explanation:

if the surface area means area of all the faces of the cube, that means 6 areas of the same length and width! multiplying the area by 6 will result in your answer :)

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I can someone evaluate this I don’t understand? Question: 8. Evaluate the piecewise-defined function at the indicated inputs.
enot [183]

Answer:

6

Step-by-step explanation:

Your function is split into 4 parts.

We want to use the piece that includes x=6.

This only included in the inequality that says x is greater than or equal to 5. Since that is, we use the expression that corresponds to that to find f(6).

f(6)=2(6)-6

f(6)=12-6

f(6)=6

4 0
3 years ago
Helpppppppppp mehhhhh plz
Goshia [24]
Let's start off with a simple y-intercept form.

y=mx + b
b represents the y intercept so we can substitute it with 2.
y = mx + 2
the point we are given, (1,1) is really just an x and y value. We can also substitute this into the equation.
y = x + 2

Now that we have some type of equation, we can convert it to the form shown in the answer choices by subtracting y from both sides.
0 = x - y + 2
Hope this helps!
4 0
3 years ago
Could you please help me thank you
stiks02 [169]

Answer:

2 (1/3) cups

Step-by-step explanation:

8 x 3(1/2) = 28 cups

28 / 12 = 2 (1/3) cups

3 0
3 years ago
Find the approximate perimeter of ABC plotted below.
maksim [4K]

Answer:

B. 21.2

Step-by-step explanation:

Perimeter of ∆ABC = AB + BC + AC

A(-4, 1)

B(-2, 3)

C(3, -4)

✔️Distance between A(-4, 1) and B(-2, 3):

AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

AB = \sqrt{(-2 - (-4))^2 + (3 - 1)^2} = \sqrt{(2)^2 + (2)^2)}

AB = \sqrt{4 + 4}

AB = \sqrt{16}

AB = 4 units

✔️Distance between B(-2, 3) and C(3, -4):

BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

BC = \sqrt{(3 - (-2))^2 + (-4 - 3)^2} = \sqrt{(5)^2 + (-7)^2)}

BC = \sqrt{25 + 49}

BC = \sqrt{74}

BC = 8.6 units (nearest tenth)

✔️Distance between A(-4, 1) and C(3, -4):

AC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

AC = \sqrt{(3 - (-4))^2 + (-4 - 1)^2} = \sqrt{(7)^2 + (-5)^2)}

AC = \sqrt{47 + 25}

AC = \sqrt{74}

AC = 8.6 units (nearest tenth)

Perimeter of ∆ABC = 4 + 8.6 + 8.6 = 21.2 units

8 0
3 years ago
Evaluate the expression when m=-6.<br> 2<br> m + 5m - 4
Brums [2.3K]

Answer:

2

Step-by-step explanation:

m^2 + 5m - 4

Let m = -6

( -6) ^2 + 5(-6) -4

Exponents first

36 + 5(-6) -4

Then multiply

36 -30 -4

Then subtract

6 -4

2

5 0
3 years ago
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