Question

(y+8)/(y^2+7)=(?)/(y^2+7)(y-8)

Answer 1

Answer:

$y^{2} - 64$

Step-by-step explanation:

$\frac{y+8}{y^{2} + 7 } = \frac{k}{(y^{2} + 7) (y-8) }$

This gives x= $y^{2} - 64$

Using the formula that $x^{2} - y^{2} = (x+y)(x-y)$