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sergeinik [125]
3 years ago
15

Grayson took out a loan for $900. In 18 months, he paid $54 in simple interest. What was the interest rate on Grayson's loan?

Mathematics
1 answer:
PolarNik [594]3 years ago
8 0

Answer:

.

Step-by-step explanation:

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Broderick had $420 in his checking account. He made 6 deposits of $35.50 each. He needs to write 4 checks for $310.75 each.How m
kvasek [131]
So, first you would need to multiply 6 by $35.50, then take that number and add it to the $420 to get $633.00. Then you need to multiply $310.75 by 4. After take that $1243.00 and subtract $633.00 from it to get $610.00. So, the answer is: Broderick would need to add at least $610 to his account to cover his checks.
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3 years ago
Write 0.000000092 in scientific notation
Leya [2.2K]

9.2x10^-8

Move the decimal to the right 8 times. Since it is moved to the right, the exponent is negative.

3 0
4 years ago
Read 2 more answers
1, 4, 13, 40, 121 what is the next number in the pattern
mart [117]
Add powers of 3.
1 + 3 = 4
4 + 9 = 13 = 4 + 3^2
13 + 27 = 40 = 13 + 3^3
40 + 81 = 121 = 40 + 3^4
Now you need to add 3^5 to 121.

121 + 3^5 = 121 + 243 = 364
7 0
3 years ago
You want to ship a box that is 10cm wide, 20 cm long and 5 cm high. What is the volume of the box?
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Step-by-step explanation:

8 0
2 years ago
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a) Suppose that a large mixing tank initially holds 300 gallons of water in which 50 pounds ofsalt have been dissolved. Pure wat
Kay [80]

Answer:

x  =  50*e∧ -t/100

Step-by-step explanation:

We assume:

1.-That the volume of mixing is always constant 300 gallons

2.-The mixing is instantaneous

Δ(x)t   =  Amount in  - Amount out

Amount  =  rate * concentration*Δt

Amount in  =  3 gallons/ min * 0  =  0

Amount out  = 3 gallons/min *  x/ 300*Δt

Then

Δ(x)t/Δt  =  - 3*x/300    Δt⇒0   lim Δ(x)t/Δt  =  dx/dt

dx/dt  =  - x/100

dx/ x  =  - dt/100

A linear first degree differential equation

∫ dx/x   =  ∫ - dt/100

Ln x  =  - t/100  +  C

initial conditions to determine C

t= 0     x =  50 pounds

Ln (50) = 0/100 * C

C =  ln (50)

Then final solution is:

Ln x  =  - t/100  + Ln(50)   or

e∧ Lnx   =  e ∧ ( -t/100 + Ln(50))

x  =  e∧ ( -t/100) * e∧Ln(50)

x  = e∧ ( -t/100) * 50

x  =  50*e∧ -t/100

4 0
3 years ago
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