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3 years ago

Whats the product of (3-2i) and (7+6i)?

Mathematics

1 answer:

Alona [7]3 years ago

6 0

Answer: the product is = 33+4i

Step-by-step explanation:

21+4i-12i^2

21+4i-12(-1) i^2=-1

21+4i+12

your answer would be 33+4i .

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3 years ago

X – 2y = 1<br> 2x + 3y = -12

lions [1.4K]

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2 years ago

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To solve y and x, I am adding a picture

Viktor [21]

Answer:

$x =\sqrt 5$

$y = \sqrt{5$

Step-by-step explanation:

Given

The attached triangle

Required

Solve for x

Considering angle 45 degrees, we have:

$\cos(45) = \frac{y}{\sqrt{10}}$ --- cosine formula i.e. adj/hyp

Solve for y

$y = \sqrt{10} * \cos(45)$

In radical form, we have:

$y = \sqrt{10} * \frac{1}{\sqrt 2}$

$y = \sqrt{10/2}$

$y = \sqrt{5$

To solve for x, we make use of Pythagoras theorem

$x^2 + y^2 = (\sqrt{10})^2$

$x^2 + y^2 =10$

Substitute for y

$x^2 + (\sqrt 5)^2 =10$

$x^2 + 5 =10$

Collect like terms

$x^2 =10-5$

$x^2= 5$

Solve for x

$x =\sqrt 5$

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3 years ago

Whats the product of (3-2i) and (7+6i)?​

Whats the product of (3-2i) and (7+6i)?