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Effectus [21]
2 years ago
5

Help plweaseeeeeekkeiwieke

Mathematics
1 answer:
7nadin3 [17]2 years ago
6 0

Answer:
Put all the first column in the box, press check. Then all 2nd column, but replace the picture with the 3rd picture. Then the 3rd column. They are all going to be right.

Step-by-step explanation:

It is arranged for you already.

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3 years ago
One gallon of paint covers 400 square feet of surface area. A typical spherical water tower holds 66,840.28 cubic feet of water.
enot [183]

Answer: There will enough to paint the outside of a typical spherical water tower.


Step-by-step explanation:

1. Solve for the radius r from the formula for calculate the volume of a sphere. as following:

V=\frac{4}{3}r^{3}\pi\\\frac{3V}{4\pi}=r^{3}\\r=\sqrt[3]{\frac{3V}{4\pi}}

2. Substitute values:

r=\sqrt[3]{\frac{3(66,840.28ft^{3})}{4\pi}}=25.17ft

3. Substitute the value of the radius into the equation fo calculate the surface area of a sphere, then you obtain that the surface area of a typical spherical water tower is:

SA=4r^{2}\pi\\SA=4(25.17ft)^{2} \pi\\SA=7,964.95ft^{2}

3. If a city has 25 gallons of paint available and one gallon of paint covers 400 square feet of surface area, you must multiply 25 by 400 square feet to know if there will be enough to paint the outside of a typical spherical water tower.

25*400ft^{2}=10,000ft^{2}

As you can see, there will enough to paint the outside of a typical spherical water tower.

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3 years ago
DETERMINE WHETHER THE EXPRESSIONS BELOW ARE CORRECT OR NOT AND DO THE CORRECTION
Assoli18 [71]

Answer:

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Step-by-step explanation:

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