A triangle cannot be both

Mathematics

1 answer:

grin007 [14]3 years ago

8 0

Answer:

the answer is A

Step-by-step explanation:

if one angle is obtuse then the other two angles will both be acute, so it cannot be a right triangle

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The first three terms of a geometric sequence are shown below.

never [62]

$a_1=x+3\\\\a_2=-2x^2-6x=-2x(x+3)\\\\a_3=4x^3+12x^2=-2x(-2x^2-6x)=-2x[-2x(x+3)]\\\vdots\\\text{The general term of geometric sequence}\ a_n=a_1r^{n-1}\\\\a_1-first\ term\\r-common\ ratio\\\\a_1=x+3,\ r=-2x\\\\\text{Substitute}\\\\a_n=(x+3)(-2x)^{n-1}\\\\8th\ term\to a_8\\\\\text{Substitute}\ n=8\ \text{to the equation of}\ a_n:\\\\a_8=(x+3)(-2x)^{8-1}=(x+3)(-2x)^7=(x+3)(-128x^7)\\\\\text{use distributive property}\\\\a_8=(x)(-128x^7)+(3)(-128x^7)\\\\\boxed{a_8=-128x^8-384x^7}$

8 0

3 years ago

3 x 5/6 = ? x 1/6

NemiM [27]

Answer:

Step-by-step explanation:

$3 \times \frac{5}{6} = \frac{15}{6} = 15 \times \frac{1}{6}$

4 0

2 years ago

Use technology to determine PLEASE HELP I WILL MARK U BRAINLIEST. the vertex of each quadratic

Arte-miy333 [17]

9514 1404 393

Answer:

vertex: (7.5, 2.25)
f(x) = -(x -7.5)² +2.25

Step-by-step explanation:

My favorite "technology" for problems like this is the Desmos graphing calculator app or web service. It easily displays the vertex (and/or zeros) of the function.

Of course, vertex form is ...

f(x) = a(x -h)² +k . . . . . . . . vertex (h, k), leading coefficient 'a'

The solution is found by reading the graph and putting the numbers in the formula. The leading coefficient is copied from the standard form equation.