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Leviafan [203]
3 years ago
8

A triangle cannot be both

Mathematics
1 answer:
grin007 [14]3 years ago
8 0

Answer:

the answer is A

Step-by-step explanation:

if one angle is obtuse then the other two angles will both be acute, so it cannot be a right triangle

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What is -7+ 1/3.<br><br><br><br><br>pos helo​
Nutka1998 [239]

Answer:

I'm not sure exactly what you mean but, here's my answer to 7 + 1/3.

22 /3

Step-by-step explanation:

5 0
3 years ago
Suppose a ball is thrown upward to a height of h 0 meters. After each​ bounce, the ball rebounds to a fraction r of its previous
gladu [14]

Answer:

A)1st term:45

2nd term:48.75

3rd term:49.6875

4th term:49.921875

B) Sₙ = h₀ + 2h₀((∞, n=1) Σrⁿ)

Step-by-step explanation:

We are given;

h₀ = Initial height of the ball = 30

r = Rebound fraction = 0.25

a) The arithmetic sequence of bouncing balls is given by the following;

Sₙ=h₀+2h₀(r¹+r²+r³+r⁴.........rⁿ)

The first term of the sequence is;

S₁ = h₀ + 2h₀r¹

S₁ = 30 + (2 × 30 × 0.25)

S₁ = 45

The second term of the sequence is;

S₂ = h₀ + 2h₀(r¹+r²)

S₂ = 30 + (2 × 30 × (0.25 + 0.25²)) = 48.75

The third term of the sequence is;

S₃ = h₀ + 2h₀(r¹ + r² + r³) = 30 + (2 × 30 × (0.25 + 0.25² + 0.25³)) = 49.6875

S₄ = h₀ + 2h₀(r¹ + r² + r³ + r⁴)

S₄ = 30 + (2 × 30 × (0.25 + 0.25² + 0.25³ + 0.25⁴)) = 49.921875

B) The general expression for the nth term of the sequence is;

Sₙ = h₀ + 2h₀((∞, n=1) Σrⁿ)

4 0
3 years ago
In a certain assembly plant, three machines B1, B2, and B3, make 30%, 20%, and 50%, respectively. It is known from past experien
diamong [38]

Answer:

The probability that a randomly selected non-defective product is produced by machine B1 is 11.38%.

Step-by-step explanation:

Using Bayes' Theorem

P(A|B) = \frac{P(B|A)P(A)}{P(B)} = \frac{P(B|A)P(A)}{P(B|A)P(A) + P(B|a)P(a)}

where

P(B|A) is probability of event B given event A

P(B|a) is probability of event B not given event A  

and P(A), P(B), and P(a) are the probabilities of events A,B, and event A not happening respectively.

For this problem,

Let P(B1) = Probability of machine B1 = 0.3

P(B2) = Probability of machine B2 = 0.2

P(B3) = Probability of machine B3 = 0.5

Let P(D) = Probability of a defective product

P(N) = Probability of a Non-defective product

P(D|B1) be probability of a defective product produced by machine 1 = 0.3 x 0.01 = 0.003

P(D|B2) be probability of a defective product produced by machine 2 = 0.2 x 0.03 = 0.006

P(D|B3) be probability of a defective product produced by machine 3 = 0.5 x 0.02 = 0.010

Likewise,

P(N|B1) be probability of a non-defective product produced by machine 1 = 1 - P(D|B1) = 1 - 0.003 = 0.997

P(N|B2) be probability of a non-defective product produced by machine 2  = 1 - P(D|B2) = 1 - 0.006 = 0.994

P(N|B3) be probability of a non-defective product produced by machine 3 = 1 - P(D|B3) = 1 - 0.010 = 0.990

For the probability of a finished product produced by machine B1 given it's non-defective; represented by P(B1|N)

P(B1|N) =\frac{P(N|B1)P(B1)}{P(N|B1)P(B1) + P(N|B2)P(B2) + (P(N|B3)P(B3)} = \frac{(0.297)(0.3)}{(0.297)(0.3) + (0.994)(0.2) + (0.990)(0.5)} = 0.1138

Hence the probability that a non-defective product is produced by machine B1 is 11.38%.

4 0
3 years ago
There are 40 people at Drake's sweet sixteen party. Drake's only rule is that everyone in the party must meet and shake each oth
nikdorinn [45]
1) This is a combination, so use ⁴⁰C₂.
     ⁴⁰C₂ = 780
     There are 780 handshakes in total.

2) I got my solution by using the combinations formula. Or another way you              could do this is to add up... 39 + 38 + 37 + 36 + 35 + 34 + 33 + 32 + 31... +1.          You will end up with 780 (I did this to double check my work).

3) The quickest way to figure this out if Drake invited 1,000 people is to use the       natural numbers formula = n(n+ 1)/2.
     Plug the numbers in: 999(1000)/2 = 499,500 
     If Drake invited 1,000 people, there would be 499,500 handshakes.

7 0
2 years ago
Read 2 more answers
Factor -12x^6-60x^5-75x^4
lesya [120]
-12x^6 - 60x^5-75x^4.......GCF = 3x^4
 3x^4(-4x^2 - 20x - 25)
3x^4(-2x - 5)(2x + 5) <==
6 0
3 years ago
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