Based on the given parameters, the value of the function h(-1) is -1
<h3>How to evaluate the function?</h3>
The equation of the function is given as:
h(t) =-t^2 + t + 1
The function is given as:
h(-1)
This means that t = -1
So, we substitute t = -1 in the equation h(t) =-t^2 + t + 1
h(-1) =-(-1)^2 + (-1) + 1
Evaluate the exponent
h(-1) =-1 - 1 + 1
Evaluate the like terms
h(-1) = -1
Hence, the value of the function h(-1) is -1
Read more about functions at:
brainly.com/question/1415456
#SPJ1
<u>Complete question</u>
Consider the following function definition, and calculate the value of the function
h(t) = −t2 + t + 1 h(−1)
Answer:
0.0208<p<0.0592
Step-by-step explanation:
-Given the sample size is 400 and the desired proportion is 16.
-The confidence interval can be determined as follows:

#We the use this proportion to find the CI at 95%:
![CI=0.04\pm 1.96\times \sqrt{\frac{0.04(1-0.04)}{400}}\\\\=0.04\pm 0.0192\\\\=[0.0208,0.0592]](https://tex.z-dn.net/?f=CI%3D0.04%5Cpm%201.96%5Ctimes%20%5Csqrt%7B%5Cfrac%7B0.04%281-0.04%29%7D%7B400%7D%7D%5C%5C%5C%5C%3D0.04%5Cpm%200.0192%5C%5C%5C%5C%3D%5B0.0208%2C0.0592%5D)
Hence, the 95% confidence interval is 0.0208<p<0.0592
28 each book 155-15=140 and then 140÷5=28
Answer:
area=
square =Side ×side
rectangle = length ×breadth
Step-by-step explanation:
hope this help you
NO. The mirror will not fit in a space that is 15 inches by 16 inches
<em><u>Solution:</u></em>
Given that area of mirror is 225 square inches

Converting the above mixed fraction we get,

Let us find the length of mirror
The area of mirror is given as:
area of mirror = length x width
Substituting the given values,

Thus length of mirror is 16.36 inches
<em><u>Will the mirror fit in a space that is 15 inches by 16 inches?</u></em>
NO. The mirror will not fit in a space that is 15 inches by 16 inches
Because length of mirror is 16.36 inches whereas the given space is 15 inches long
16.36 > 15 so the length of mirror will not fit inside the space
Also width of mirror is
inches which is less than the given space whose width is 16 inches
13.75 < 16 so the width of mirror will not fit inside the space