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ANTONII [103]
2 years ago
5

A scientist selected a random sample of seven varieties of peach ice cream to investigate the relationship between the density,

in pounds per cubic inch, of the varieties of ice cream and the percent concentration of peaches in the ice cream. Assuming all conditions for inference are met, which of the following significance tests should be used to investigate whether there is convincing evidence at the 0.05 level of significance that a greater percent of peaches in the ice cream is associated with an increase in the density of the ice cream?
A. A two-sample t-test for a difference between means

B. A chi-square test of independence

C. A linear regression t-test for slope

D. A two-sample z-test for a difference between proportions

E. A matched pairs t-test for a mean difference
Mathematics
1 answer:
ValentinkaMS [17]2 years ago
7 0

Answer:

The significance test that would be used to investigate whether there is convincing evidence at 0.05 level of significance that a greater percent of peaches in the ice cream is associated with an increase in the density of the ice cream is option C;

C. A linear regression t-test for slope

Step-by-step explanation:

The linear regression t-test for slope is a test for determining the existence of a statistically significant linear relationship between two variables, a independent variable, X and an dependent variable Y in the following form;

Y = B₀ + B₁·X

The test is used to test the regression line slope where we have;

B₀ = The constant

B₁ = The slope also known as the regression coefficient

The given information tested in the question is if an increase in the peaches in the ice cream is associated with an increase in the density of the ice cream, therefore, the test to investigate the relationship between the rate of both variables is the linear regression t-test for slope.

Therefore, we have

Y = B₀ + B₁·X

Where;

X = The percentage of peaches in the ice cream

Y = The density of the ice cream

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Use the sample information 11formula13.mml = 37, σ = 5, n = 15 to calculate the following confidence intervals for μ assuming th
bija089 [108]

Answer & Step-by-step explanation:

The confidence interval formula is:

I (1-alpha) (μ)= mean+- [(Z(alpha/2))* σ/sqrt(n)]

alpha= is the proposition of the distribution tails that are outside the confidence interval. In this case, 10% because 100-90%

σ= standard deviation. In this case 5

mean= 37

n= number of observations. In this case, 15

(a)

Z(alpha/2)= is the critical value of the standardized normal distribution. The critical valu for z(5%) is 1.645

Then, the confidence interval (90%):

I 90%(μ)= 37+- [1.645*(5/sqrt(15))]

I 90%(μ)= 37+- [2.1236]

I 90%(μ)= [37-2.1236;37+2.1236]

I 90%(μ)= [34.8764;39.1236]

(b)

Z(alpha/2)= Z(2.5%)= 1.96

Then, the confidence interval (90%):

I 95%(μ)= 37+- [1.96*(5/sqrt(15)) ]

I 95%(μ)= 37+- [2.5303]

I 95%(μ)= [37-2.5303;37+2.5303]

I 95%(μ)= [34.4697;39.5203]

(c)

Z(alpha/2)= Z(0.5%)= 2.5758

Then, the confidence interval (90%):

I 99%(μ)= 37+- [2.5758*(5/sqrt(15))

I 99%(μ)= 37+- [3.3253]

I 99%(μ)= [37-3.3253;37+3.3253]

I 99%(μ)= [33.6747;39.3253]

(d)

C. The interval gets wider as the confidence level increases.

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3 years ago
Which of the following is the solution to the inequality -5x + 20 < 130?
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The answer is B. x > -22


-5x + 20 < 130

-5x < 130 - 20

-5x < 110

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x > -22
6 0
2 years ago
When salt and water are combined, they form a salt or saline solution. How much ml of water must be added to 150 mL of an 80% sa
Vinvika [58]

Answer:

We must add 400 ml of water.

Step-by-step explanation:

We can use the following equation:

C_{i}V_{i}=C_{f}V_{f}

Where:

  • C(i) is the initial concentration of the solution (80%)
  • C(f) is the final concentration of the solution (30%)
  • V(i) is the initial volume (150 ml)
  • V(f) is the final volume

Now, we just need to solve the equation for V(f).

V_{f}=\frac{C_{i}V_{i}}{C_{f}}

V_{f}=\frac{80*150}{30}

V_{f}=400\: ml

Therefore, we must add 400 ml of water.

I hope it helps you!

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Answer:

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Step-by-step explanation:

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