1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Gnoma [55]
3 years ago
10

When light travels from one medium to another with a different index of refraction, how is the light's frequency and wavelength

affected
Physics
1 answer:
lbvjy [14]3 years ago
6 0

Answer:

The frequency does not change, but the wavelength does

Explanation:

Here are the options

A. When a light wave travels from a medium with a lower index of refraction to a medium with a higher index of refraction, the frequency changes and the wavelength does not.

B. The frequency does change, but the wavelength remains unchanged.

C. Both the frequency and wavelength change.

D. When a light wave travels from a medium with a lower index of refraction to a medium with a higher index of refraction, neither the wavelength nor the frequency changes.

E. The frequency does not change, but its wavelength does.

When light goes through one medium to the next, the frequency doesn't really change seeing as frequency is dependent on wavelength and light wave velocity. And when the wavelength shifts from one medium to the next.

n= \frac{C}{V} \ and\ \frac{\lambda_o}{\lambda_m}

where \lambda_o indicates wavelength in vacuum

\lambda_m indicates wavelength in medium

n indicates refractive index

v indicates velocity of light wave

c indicates velocity of light

And wavelength is medium-dependent. Frequency Here = v\lambda and shift in wavelength and velocity, not shifts in overall frequency.

Therefore the correct option is E

You might be interested in
A 4000-? resistor is connected across a 220-V power source. What current will flow through the resistor?
Varvara68 [4.7K]

Answer:

55 mA

Explanation:

Ohm's law states:

V = IR

where V is voltage, I is current, and R is resistance.

220 V = I (4000 Ω)

I = 0.055 A

I = 55 mA

7 0
3 years ago
A block of cheese is sliding up an inclined surface that is not smooth.
labwork [276]

Answer:

I cant fit the entire picture but this should help

5 0
3 years ago
Read 2 more answers
What best describe the location of an atom's electrons
Alex_Xolod [135]
Electrons circle the outside of the nucleus.
6 0
3 years ago
Read 2 more answers
Anna is conducting an experiment to determine how weather affects cell phone reception. She is trying to decide the best way to
aev [14]

Answer:

D. Test a cell phone's reception in the exact same location under various atmospheric conditions

Explanation:

Components of an experiment:

Independent variable:

A manipulated variable, in an experiment or study, whose presence or degree incurs a change in the  dependent variable.

Dependent variable:

A variable which is being studied in the experiment and is supposed to change with respect to the independent variable.

Control variable:

Control variable includes the variables which are of no concern in the experiment and must be constant so that they do not interfere with the results of the experiment. Change in control variable might affect the results of an experiment.

In Anna's experiment, the independent variable is the atmospheric conditions. The dependent variable is cell phone reception that will change according to the atmospheric conditions. All other things related to the experiment are control variables like cellphone, location of the cell phone. Both of these must stay constant to collect the best data.

Hence, the best option is D.

4 0
4 years ago
Given that the CFL bulb is rated at 10% efficiency, if the LED bulb consumes half the amount of electrical power, for the same a
Butoxors [25]

Answer and explanation:

The efficiency of the LED bulb is 20% while The efficiency of the Inc bulb is 1%.

The lightbulb efficiency can be defined as the quotient between the amount of usable light and the amount of electrical power output. For the efficiency of the CFL Bulb:

\epsilon_{CFL}=\frac{L_0}{P_0}=0.1

Therefore:

\epsilon_{led}=\frac{L_0}{0.5P_0}=2 \cdot0.1=0.2\\\epsilon_{INC}=\frac{L_0}{10P_0}=0.1 \cdot 0.1=0.01

4 0
3 years ago
Other questions:
  • In which situations is the principle of crosscutting relationships useful in determining relative age check all that apply
    8·1 answer
  • 5 blocks east and 2 blocks north and 6 blocks and then 8 blocks south. what's the total distance traveled?
    10·1 answer
  • What is resolution of the vector
    6·1 answer
  • The water drops should already be dripping from the faucet. You can increase their frequency and amplitude by using the Frequenc
    7·2 answers
  • PLEASE HELP I can't figure it out
    5·1 answer
  • One characteristic of a lagoon is often
    13·1 answer
  • Give reason the si syetem of units is better than the mks system​
    12·1 answer
  • A radioactive isotope has a half life for 14 days. It had an initial count rate of 36000 Bg. What will the count rate be after 1
    14·1 answer
  • Sorry if it’s a bit blurry. But thanks for answering if you do!
    12·2 answers
  • A rock falls to the ground with a force of 300N and air resistance pushes back up on the rock with a
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!