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3 years ago

PLEASE HELP I can't figure it out

Physics

1 answer:

PSYCHO15rus [73]3 years ago

4 0

D. I know that like the back of my hand

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Why is the study of black holes important?

mariarad [96]

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2 years ago

Match the object to the type of motion it's displaying. which letter goes with which number?

makkiz [27]

Hello There!!

I think the best answer choice is:

A.  $Linear$ $motion$

B.  $Rotational$ $motion$

D. $Vibrational$ $motion$

4. $Runners$ $sprinting$ $across$ $a$ $straight$ $track$

C. $Curvilinear$ $motion$

3. $Music$ $being\\\\\\$ $played$ $on$ $a$ $stringed$ $instrument,$ $such$ $as$ $a$ $guitar$

2.  $A$ $car$ $driving$ $up$ $a$ $winding$ $mountain$ $road$

1.  $The$ $propeller$ $of$ $an$ $aircraft$ $in$ $midair$

I'm not sure this is 100% right....

P.S Tell me if this is wrong....

$Hope This Helps$ $Sangwoo!!$

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2 years ago

The orbital radius of the Earth (from Earth to Sun) is 1.496 x 10^11 m.

mrs_skeptik [129]

Explanation:

The orbital radius of the Earth is $r_1=1.496\times 10^{11}\ m$

The orbital radius of the Mercury is $r_2=5.79 \times 10^{10}\ m$

The orbital radius of the Pluto is $r_3=5.91 \times 10^{12}\ m$

We need to find the time required for light to travel from the Sun to each of the three planets.

(a) For Sun -Earth,

Kepler's third law :

$T_1^2=\dfrac{4\pi ^2}{GM}r_1^3$

M is mass of sun, $M=1.989\times 10^{30}\ kg$

So,

$T_1^2=\dfrac{4\pi ^2}{6.67\times 10^{-11}\times 1.989\times 10^{30}}\times 1.496\times 10^{11}\\\\T_1=\sqrt{\dfrac{4\pi^{2}}{6.67\times10^{-11}\times1.989\times10^{30}}\times1.496\times10^{11}}\\\\T_1=2\times 10^{-4}\ s$

(b) For Sun -Mercury,

$T_2^2=\dfrac{4\pi ^2}{6.67\times 10^{-11}\times 1.989\times 10^{30}}\times 5.79 \times 10^{10}\ m\\\\T_2=\sqrt{\dfrac{4\pi^{2}}{6.67\times10^{-11}\times1.989\times10^{30}}\times 5.79 \times 10^{10}}\ m\\\\T_2=1.31\times 10^{-4}\ s$

$T_3^2=\dfrac{4\pi ^2}{6.67\times 10^{-11}\times 1.989\times 10^{30}}\times 5.91 \times 10^{12}\\\\T_3=\sqrt{\dfrac{4\pi^{2}}{6.67\times10^{-11}\times1.989\times10^{30}}\times 5.91 \times 10^{12}}\\\\T_3=1.32\times 10^{-3}\ s$