Isosceles trapezoid abcd has diagonals ac and bd if ac=5x+13

Which number line shows the solution to 2/3x - 5 > 3

NNADVOKAT [17]

Answer:

3

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

The smallest composite number that can be written as a product of 4 different prime number are

german

Option b
Hope it helps you

8 0

3 years ago

Two cargo ships spot a signal fire on a small island. The captains know they are 140 feet

Irina18 [472]

The distance from Ship B to the signal fire at point C is $405.4 \mathrm{ft}$

Explanation:

It is given that two ships A and B are at a distance 140 ft from each other.

The angle formed by ship A is 82º and the angle formed by ship B is 78º.

To determine the distance from ship B to the signal fire at point C, we need to know the another angle.

Hence, we have,

$\begin{aligned}\angle A+\angle B+\angle C &=180^{\circ} \\82^{\circ}+78^{\circ}+\angle C &=180^{\circ} \\160^{\circ}+\angle C &=180^{\circ} \\\angle C &=20^{\circ}\end{aligned}$

Now, we shall solve the problem using the law of sines,

$\frac{\sin A}{a}=\frac{\sin C}{c}$

Substituting the values, we have,

$\frac{\sin 82^{\circ}}{a}=\frac{\sin 20^{\circ}}{140}$

$\frac{0.9903}{a}=\frac{0.3420}{140}$

Simplifying, we get,

$a=\frac{0.9903 \times 140}{0.3420}$

$a=405.4$

Thus, the distance from Ship B to the signal fire at point C is $405.4 \mathrm{ft}$

4 0

3 years ago

What are the values of a, b, and c in the quadratic equation 0 = one-halfx2 – 3x – 2?

madam [21]

Answer:

b

Step-by-step explanation:

ax^2+bx+c=0

1/2x^2-3x-2=0

7 0

3 years ago

At a bus station, buses begin their routes at 6.am. The schedule for two of the buses is based on time intervals listen below-

Anastaziya [24]

Answer:

Part A: The two buses leave the bus station at 7 : 15 am

Part B: The steamboat travels 25 miles per hour

Step-by-step explanation:

* Lets explain how to solve the problem

Part A

- Buses begin their routes at 6 am at a bus station

- Bus A leaves every 75 minutes

- Bus B leaves every 15 minutes

- We want to know the next time Bus A and Bus B will leave the bus

station at the Same time

# Bus A

∵ Bus A leaves every 75 minutes

- Lets change 75 minutes to hours and minutes

∵ 1 hour = 60 minutes

∴ 75 minutes = 75/60 = 5/4

- Change 5/4 to mixed number

∵ 5/4 = 1 1/4

∴ 75 minutes = 1 1/4 hours

- Lets change 1/4 hour to minutes

∴ 1/4 × 60 = 15 minutes

∴ 75 minutes = 1 hour and 15 minutes

∵ Bus A leaves the station at 6 am

- Add 1 hour and 15 minutes to that time

∵ 6 + 1 : 15 = 7 : 15

∴ Bus A leaves the station nest time at 7 : 15 am

# Bus B

∵ Bus B leaves every 15 minutes

∵ Bus B leaves the station at 6 am

- Add 15 minutes to 6 am

∴ Bus B leaves the station next time at 6 : 15 am

- Add another 15 minutes for next time

∴ Bus B leaves the station next time at 6 : 30 am

- Add another 15 minutes for next time

∴ Bus B leaves the station next time at 6 : 45 am

- Add another 15 minutes for next time

∵ 15 + 45 = 60 ⇒ add 6 by 1 because 60 minutes = 1 hour

∴ Bus B leaves the station next time at 7 am

- Add another 15 minutes for next time

∴ Bus B leaves the station next time at 7 : 15 am

- The 2 buses leave the station at the same time again at 7:15 am

* The two buses leave the bus station at 7 : 15 am

Part B

- It takes a steamboat 12 hours to travel 300 miles

- We need to find how many miles it travels per hour

∵ The steamboat travels 300 miles in 12 hours

- Divide the distance by the time to find its rate

∵ 300 ÷ 12 = 25

- That means it travels 25 miles per hour

∴ The steamboat travels 25 miles per hour

3 0

3 years ago