Question

(Quadratics) find the maximum of -16x^2 + 64x +8

Answer 1

Answer:

The max of this function is 72.

Step-by-step explanation:                                    -b

The x-coordinate of the vertex is given by x = ---------

                                                                               2(a)

which in this case is x = 2.

The value of -16x^2 + 64x +8 at x = 2 is f(2) = 72.

The max of this function is 72.