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olga nikolaevna [1]
3 years ago
5

Solve the system of equations using elimination. 2x + y = 9 8x – 2y = 6

Mathematics
1 answer:
Anika [276]3 years ago
4 0
<span>(1) 2x + y = 9
</span><span>(2) 8x – 2y = 6
</span>
You can eliminate the x or the y. I am going to eliminate the y

First multiply the first equation 2x + y = 9  by 2.
2x + y = 9
2(2x + y = 9)
4x +2y = 18
Now we have a new equation that we can use and we can eliminate the y from the other equation because +2y - 2y = 0. Lets do that now and solve for  x.

4x +2y = 18
8x – 2y = 6
12x = 24
12x / 12 = 24 / 12
x = 2
So we found the value of x, which is 2. To find y, insert 2 into one of the original equations. I am going to use 2x + y = 9
2x + y = 9
2(2) + y = 9
4 + y = 9
-4 + 4 + y = 9 - 4
y = 9 - 4
y = 5
y = 5.

Our point is at (x, y) = (2,5)
x = 2
y = 5

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Answer:

The probability that all are male of choosing '3' students

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Step-by-step explanation:

Let 'M' be the event of selecting males n(M) = 12

Number of ways of choosing 3 students From all males and females

n(M) = 28C_{3} = \frac{28!}{(28-3)!3!} =\frac{28 X 27 X 26}{3 X 2 X 1 } = 3,276

Number of ways of choosing 3 students From all males

n(M) = 12C_{3} = \frac{12!}{(12-3)!3!} =\frac{12 X 11 X 10}{3 X 2 X 1 } =220

The probability that all are male of choosing '3' students

P(E) = \frac{n(M)}{n(S)} = \frac{12 C_{3} }{28 C_{3} }

P(E) =  \frac{12 C_{3} }{28 C_{3} } = \frac{220}{3276}

P(E) = 0.067 = 6.71%

<u><em>Final answer</em></u>:-

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

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