Answer
g(x) = x^3 − x^2 − 4x + 4
End behavior- Falls to the left rises to the right
y intercept-(0, 4)
Zeros- (1,-2,2)
g(x) = x^3 + 2x^2 − 9x − 18
End behavior- Falls to the left rises on the right
y intercept- (0,-18)
Zeros- (-2,-3,3)
g(x) = x^3 − 3x^2 − 4x + 12
End behavior-Falls to the left rises to the right
y intercept-(0,12)
Zeros- (3,-2,2)
g(x) = x^3 + 2x^2 − 25x − 50
End behavior- falls to the left rises to the right
y intercept(0,-50)
Zeros- (-2,-5,5)
g(x) = 2x^3 + 14x^2 − 2x − 14
End behavior- falls to the left rises to the right
y intercept-(0,-14)
Zeros- (-7,-1,1)
Step-by-step explanation:
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Answer:
Step-by-step explanation:
<u>System of Equations</u>
Let's call:
x = number of nickels in the student's pocket
y = number of dimes in the student's pocket
Each nickel has a value of $0.05, so x nickels have a value of 0.05x
Each dime has a value of $0.10, so y dimes have a value of 0.10y
The student has a total of 10 coins, thus:
The total value of the coins is $0.85, thus
The system of linear equations that represents this scenario is:
5a + s = 2662
a + s = 1198
4a = 1464
a = 366
5(366) + s = 2,662
1830 adult tickets sold
2662 - 1830 = 832
832 student tickets sold
Answer: approximately 29 feet
Explanation: You need to find a tree so that the angle of elevation from the end of the shadow to top of the tree is 40 degrees.
The length of the shadow is an adjacent side and is 35.
The height of the tree is the opposite side. You could use X.
Tan ratio = opposite/adjacent
tan(40) = x/35
x = 35*tan(40) =29.37
