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vaieri [72.5K]
3 years ago
13

Identify a point, that when graphed on the coordinate system, makes the relation not a function. E X P L A I N.

Mathematics
1 answer:
xeze [42]3 years ago
4 0
The coordinates of points in the graph are,

(-4,-1), (-2,1), (0,-3), (2,3)
and

(4,-2)
Any other point whose first coordinate(the x-co-ordinate) coincides with one of these points will make the relation not a function.

The relation becomes one- to-many relation which is not a function.

It will also fail the vertical line test , if the points are connected with line segments.

One of such point is,

(4,3)
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If a building is 1,065 feet tall. Starting from a height of 60 feet , windows 15 feet tall are used on the outside of the buildi
sleet_krkn [62]

1,065 - 60 = 1,005

1,005 / 15 = 67 windows

60ft is 4 windows

7 0
3 years ago
Show all work please!!!!!!
sergij07 [2.7K]
The midpoint formula is:
(point1 + point2)/2

1) (-2 + 12)/2 = 5

2) (-1 +5)/2 = 2
    (0+2)/2 = 1
     (2,1)

3) Sqrt of (x2-x1)^2 + (y2 - y1)^2
     sqrt of (7 -1)^2 + (-7 - 1)^2
     sqrt of (6)^2 + (-8)^2
     sqrt of 36 + 64
     sqrt of 100
     10

Hope this helps!
7 0
3 years ago
If  the three angles  of  a quadrilateral are 120,  130, 10 then the fourth angle is​
Aloiza [94]

Answer:

100

Step-by-step explanation:

120 + 130 + 10 = 260

360 - 260 = 100

4 0
2 years ago
Read 2 more answers
1) After a dilation, (-60, 15) is the image of (-12, 3). What are the coordinates of the image of (-2,-7) after the same dilatio
BARSIC [14]

Answer:

a) k = 5; (-10, -35)

Step-by-step explanation:

Given:

Co-ordinates:

Pre-Image = (-12,3)

After dilation

Image = (-60,15)

The dilation about the origin can be given as :

Pre-Image(x,y)\rightarrow Image(kx,ky)

where k represents the scalar factor.

We can find value of k for the given co-ordinates by finding the ratio of x or y co-ordinates of the image and pre-image.

k=\frac{Image}{Pre-Image}

For the given co-ordinates.

Pre-Image = (-12,3)

Image = (-60,15)

The value of k=\frac{-60}{-12}=5

or k=\frac{15}{3}=5

As we get k=5 for both ratios i.e of x and  y co-ordinates, so we can say the image has been dilated by a factor of 5 about the origin.

To find the image of (-2,-7), after same dilation, we will multiply the co-ordinates with the scalar factor.

Pre-Image(-2,-7)\rightarrow Image((-2\times5),(-7\times 5))

Pre-Image(-2,-7)\rightarrow Image(-10,-35) (Answer)

7 0
2 years ago
Why does sin54°≈0.809≈cos36° in a right triangle?
allsm [11]

9514 1404 393

Answer:

A

54° and 36° are complementary angles in the same right triangle. sin54° is the ratio of the opposite leg and the hypotenuse and cos36° is the ratio of the adjacent leg and the hypotenuse. In this triangle, the opposite leg of 54° and the adjacent leg of 36° are the same leg in the triangle.

Step-by-step explanation:

The answer explains itself.

The sum of angles in a triangle is 180°. When one of the angles is 90°, the sum of the other two angles is also 90°. That means those two acute angles are <em>complementary</em> (not supplementary).

The mnemonic SOH CAH TOA reminds you that ...

  Sin = Opposite/Hypotenuse

  Cos = Adjacent/Hypotenuse

7 0
2 years ago
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