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3 years ago

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Find the dimensions of a rectangle with area 2,197 m2 whose perimeter is as small as possible.

1 answer:

Flura [38]3 years ago

8 0

The area of a rectangle is calculated by multiplying its length and width. That is,
A = L x W
Given that area is 2,197, the width is 2197/L. The perimeter on the other hand is the twice the sum of the dimensions. That is,
P = 2L + 2(2197/L)
Differentiating the equation and equating the differential to zero.
dP = 2 + 4394(-1/L²) = 0
Solving for L will give us an answer of 46.87 m. Thus, the length and the width of the rectangle are approximately 46.87 m both.

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Step-by-step explanation:

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Tcecarenko [31]

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Vesna [10]

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4 years ago

Find the missing side of the triangle. Round your answers to the nearest tenth if necessary.

Oliga [24]

Answer:

6.5cm)

Step-by-step explanation:

13.1 cm x 13.1 cm = 171.61

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171.61 - 129.96 = 41.65

Find the square root of 41.65.

41.65 = 6.4536811201050 x 6.4536811201050

Round 6.4536811201050.

x = 6.5cm

Note:

Pls let me know if my answer is incorrect, for the other users that will see this response. Thx!

<em>-kiniwih426</em>

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Ne4ueva [31]

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