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Julli [10]
3 years ago
10

For this linear equation, give the number by which you would multiply the terms in each equation in order to eliminate one of th

e variables. Then solve this system:
5x+2y=-1; 3x+7y=11

This would be a big help if you also include the process to help me understand the answer!
Mathematics
2 answers:
Nadya [2.5K]3 years ago
7 0

Answer:

Step-by-step explanation:

If we choose to eliminate x, multiply the first equation by -3:  -15x - 6y = 3

and multiply the second by 5:  -15x - 35y = 55

Note that this allows us to eliminate x.  We get:

-6y = 3

-35y = 55

which sum up to -41y = 58.  Thus, y = -58/4.

Leya [2.2K]3 years ago
6 0

Answer:

Step-by-step explanation:

The solution to this system of linear equations 3x – 2y = 14 and 5x + y = 32 is (x, y) is (6, 2).

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Solution :

Given :

2y''' + 15y'' + 24y' + 11y= 0

Let x = independent variable

(a_0D^n + a_1D^{n-1}+a_2D^{n-2} + ....+ a_n) y) =  Q(x)  is a differential equation.

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2y''' + 15y'' + 24y' + 11y= 0

$(2D^3+15D^2+24D+11)y=0$

Auxiliary equation,

$2m^3+15m^2+24m +11 = 0$

-1  | 2    15    24     11

   <u> | 0   -2    - 13    -11  </u>

      2    13    11       0

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$=\frac{-13\pm \sqrt{13^2-4(11)(2)}}{2(2)}$

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$=-5.5, -1$

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$= (c_1+c_2 x)e^{-x} + c_3 \ e^{-5.5x}$

 

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