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Julli [10]
3 years ago
10

For this linear equation, give the number by which you would multiply the terms in each equation in order to eliminate one of th

e variables. Then solve this system:
5x+2y=-1; 3x+7y=11

This would be a big help if you also include the process to help me understand the answer!
Mathematics
2 answers:
Nadya [2.5K]3 years ago
7 0

Answer:

Step-by-step explanation:

If we choose to eliminate x, multiply the first equation by -3:  -15x - 6y = 3

and multiply the second by 5:  -15x - 35y = 55

Note that this allows us to eliminate x.  We get:

-6y = 3

-35y = 55

which sum up to -41y = 58.  Thus, y = -58/4.

Leya [2.2K]3 years ago
6 0

Answer:

Step-by-step explanation:

The solution to this system of linear equations 3x – 2y = 14 and 5x + y = 32 is (x, y) is (6, 2).

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I need answers to this
ololo11 [35]

Answer:

x = -5, and y = -6

Step-by-step explanation:

Suppose that we have two equations:

A = B

and

C = D

combining the equations means that we will do:

First we multiply both whole equations by constants:

k*(A = B) ---> k*A = k*B

j*(C = D) ----> j*C = j*D

And then we "add" them:

k*A + j*C = k*B + j*D

Now we have the equations:

-x  - y = 11

4*x - 5*y = 10

We want to add them in a given form that one of the variables cancels, so we can solve it for the other variable.

Then we can take the first equation:

-x  - y = 11

and multiply both sides by 4.

4*(-x - y = 11)

Then we get:

4*(-x - y) = 4*11

-4*x - 4*y = 44

Now we have the two equations:

-4*x - 4*y = 44

4*x - 5*y = 10

(here we can think that we multiplied the second equation by 1, then we have k = 4, and j = 1)

If we add them, we get:

(-4*x - 4*y) + (4*x - 5*y) = 10 + 44

-4*x - 4*y + 4*x - 5*y = 54

-9*y = 54

So we combined the equations and now ended with an equation that is really easy to solve for y.

y = 54/-9 = -6

Now that we know the value of y, we can simply replace it in one of the two equations to get the value of x.

-x - y = 11

-x - (-6) = 11

-x + 6 = 11

-x = 11 -6 = 5

-x = 5

x = -5

Then:

x = -5, and y = -6

5 0
3 years ago
The senior classes at high school A and high school B planned separate trips to New York City. The senior class at high school A
alexdok [17]
13 bus seats on each bus and 12 seats on each van
8 0
3 years ago
Simplify the following:<br> 3÷4i 15÷2-3i
seropon [69]

Answer:

7i=4.5

Step-by-step explanation:

Hope this helps

7 0
3 years ago
Raymond just got done jumping at Super Bounce Trampoline Center. The total cost of his session was $43.25dollar sign, 43, point,
mars1129 [50]

Answer:

The equation that represents the money he spent by the time he was on the trampoline is "total amount = 7 + 1.25*x" and on that day he spent 29 minutes on the trampoline.

Step-by-step explanation:

The question is incomplete, but we can assume that the problems wants us to determine an equation for the time in minutes that Raymond spent on the Super Bounce.

In order to write this equation we will attribute a variable to the amount of time Raymond spent on the trampoline, this will be called "x". There were two kinds of fees to ride the trampoline, the first one was a fixed fee of $7 while the second one was a variable fee of $ 1.25 per minnute spent playing. So we have:

total amount = 7 + 1.25*x

Since he spent a total of $43.25 on that day we have:

1.25*x + 7 = 43.25

1.25*x = 43.25 - 7

1.25*x = 36.25

x = 36.25/1.25 = 29 minutes

The equation that represents the money he spent by the time he was on the trampoline is "total amount = 7 + 1.25*x" and on that day he spent 29 minutes on the trampoline.

6 0
3 years ago
What are the minimum, first quartile, median, third quartile, and maximum of the data set? 2, 13, 17, 14, 9, 3, 16, 12
Alex777 [14]

So before anything, rearrange the data so that it's in ascending order: {2,3,9,12,13,14,16,17}

Next, the minimum and maximum are as they seem: the smallest and largest numbers in the data. Looking at our data, <u>2 is our minimum and 17 is our maximum.</u>

Next, to find the median, find the number that is in the middle of the data set. If there isn't one number in the middle, find the average of the two middle numbers to get your median:

\{2,3,9,\overbrace{\boxed{12,13,}}^{\textsf{middle numbers}}14,16,17\}\\\\\frac{12+13}{2}\\\\\frac{25}{2}\\\\12.5

<u>The median is 12.5.</u>

Next, to find the first quartile, or the lower quartile, find the "median" of the numbers to the left of the median.

\overbrace{\{2,\boxed{3,9,}12,}^{\textsf{left of median}}13,14,16,17\}\\\\\frac{3+9}{2}\\\\\frac{12}{2}\\\\6

<u>The first quartile is 6.</u>

Next, to find the third quartile, or the upper quartile, find the "median" of the numbers to the right of the median.

\{2,3,9,12,\overbrace{13,\boxed{14,16,}17\}}^{\textsf{right of median}}\\\\\frac{14+16}{2}\\\\\frac{30}{2}\\\\15

<u>The third quartile is 15.</u>

3 0
3 years ago
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