Answer:
$251,618 is the answer
Step-by-step explanation:
Answer:
x = 3 and y = 2
or
(3,2)
Step-by-step explanation:
first equation (LCM = 3 x 4 x 5 = 60)
(x+2)/5 - (9-x)/3 = (y - 6)/4
12(x+2) - 20(9-x) = 15(y - 6)
12x + 24 - 180 + 20x = 15y - 90
32x - 15y = -90 - 24 + 180
32x - 15y = 66
second equation:
8(x + 2) - (2x + y) = 2(x + 13)
8x + 16 - 2x - y = 2x + 26
6x - y + 16 = 2x + 26
4x - y = 10
Now you have 2 equations:
4x - y = 10 ---> y = 4x - 10
32x - 15y = 66
Substitute y = 4x - 10 into 32x - 15y = 66
32x - 15(4x - 10) = 66
32x - 60x + 150 = 66
-28x = -84
x = 3
y = 4(3) - 10
y = 12 - 10
y = 2
Solutions: x = 3 and y = 2
Well it depends. what the problem
Answer:
Yes we can conclude.
Step-by-step explanation:
The sampling distribution of 
can be approximated as a Normal Distribution only if:
np and nq are both equal to or greater than 10. i.e.
Both of these conditions must be met in order to approximate the sampling distribution of as Normal Distribution.
From the given data:
n = 50
p = 0.80
q = 1 - p = 1 - 0.80 = 0.20
np = 50(0.80) = 40
nq = 50(0.20) = 10
This means the conditions that np and nq must be equal to or greater than 10 is being satisfied. So, we can conclude that the sampling distribution of pˆ is approximately a normal distribution
