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Semmy [17]
2 years ago
13

The question is in the attached file

Mathematics
2 answers:
sp2606 [1]2 years ago
6 0

\textsf {Applying this formula :}

\mathsf {(x) \times (y) =\sqrt{x^{2} + y^{2}}}

\textsf {Now take :}

\mathsf {x = 2}\\\mathsf {y = 4\sqrt{2}}

\mathsf {Solving :}

\implies \mathsf {\sqrt{(2)^{2} + (4\sqrt{2})^{2}}}

\implies \mathsf {\sqrt{4 + 32}}

\implies \mathsf {6}

sergeinik [125]2 years ago
3 0

Answer:

C

Step-by-step explanation:

using

x × y = \sqrt{x^2+y^2} , then

2 × 4\sqrt{2}

= \sqrt{2^2+(4\sqrt{2})^2 }

= \sqrt{4+32}

= \sqrt{36}

= 6

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Answer:

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Step-by-step explanation:

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3 years ago
Suppose you pick 6 different numbers in [10]. Prove that 2 of the numbers are next to each other. (Hint: use the pigeonhole prin
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Step-by-step explanation:

We are picking 6 numbers from the numbers 1,2,3,4,5,6,7,8,9,10. Since we care about numbers being next to each other, we might think of the 10 numbers as being distributed in 5 boxes (which you can think of as the holes):

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4 0
4 years ago
Help please!!!!! I will thanks and medal.
galina1969 [7]
Your answer would be 3
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3 years ago
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